Remark
You know the most about the trip on the way back and the total of the two trips.
Way Back
r = 30 mph
d = distance traveled
t = t - 1 where t = the time to go there which we know nothing about
Total Distance
2d = 25 mph * (t + t - 1)
2d = 25 * (2t - 1)
2d = 50t - 25 Divide by 2
2d = 50t/2 - 25/2
d = 25t - 12.5
Equation coming back
d = 30*(t - 1)
d = 30t - 30
Comment
Since the distances are the same, equate them.
Solution
25t - 12.5 = 30t - 30 Subtract 25t from both sides
25t - 25t -12.5 = 30t - 25t - 30 Combine like terms
-12.5 = 5t - 30 Add 30 to both sides
-12.5 + 30 = 5t - 30 + 30 Combine
17.5 = 5t Divide by 5
17.5/5 = t Divide and Switch
t = 3.5
t is the time going there
t - 1 is the time coming back
Total time = 2*t - 1 = 2*3.5 - 1 = 6
The total time is 6 hours. Answer
Answer:
Option A. 6.247°
Step-by-step explanation:
we know that
1°=60'
1'=60"
we have
6° 14' 48"
Convert to decimal form
<em>Convert seconds to minutes</em>
48"=48/60=0.8'
so
6° 14' 48"=6° + 14' +0.8'=6° 14.8'
<em>Convert minutes to degrees</em>
14.8'=14.8/60=0.247°
so
6° 14.8' =6° + 0.247°=6.247°
Answer:
No, 60 is the third interior angle's mesure, not the exterior ∠3.
Step-by-step explanation:
Say that ∠1=∠A=50 and ∠2=∠B=70. The remote interior angles are the angles that are not touvhing the exterior angle. So ∠3 would be the the exterior angle to ∠C. ∠C=60 as the sum of the interior angles is 180.
The exterior angle is the angle formed by extending one of the triangle's sides. A straight line has the angle 180, so∠3=180-∠C=180-60=120.
Answer:
The answer is 0.7036.
Step-by-step explanation:
Check the attached file for the computations.
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