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soldi70 [24.7K]
3 years ago
6

X - 7y - 10 - x - 7y + 10 x - 7y + 10 Find the quotient. (5x - 35y + 50) ÷ 5

Mathematics
2 answers:
rusak2 [61]3 years ago
7 0

Answer:

x+10-7y OR x - 7y + 10, same thing.

Step-by-step explanation:

Start of by factoring (5x - 35y + 50) = 5\left(x+10-7y\right)

You can put it into a dividing equation: \frac{5\left(x+10-7y\right)}{5}\\

The 5 will cancel out, leaving you answer!

Hope this helps!!

weqwewe [10]3 years ago
3 0

Answer:

Divide each term by 5, looking at the coefficients. The answer is x - 7y + 10


Step-by-step explanation:


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MA_775_DIABLO [31]

Answer:

\int_R 15x+15y dA = \frac{8}{16875}

Step-by-step explanation:

Recall the following: x = 15u+15v, y = -60u+15v. So, x-y = 75u. Then u = (x-y)/75. 4x+y = 75v. Then v = (4x+y)/75.

We will see how this transformation maps the region R to a new region in the u-v domain. To do so, we will see where the transformation maps the vertices of the region.

(-1,4) -> ((-1-4)/75,(4(-1)+4)/75) = (-1/15, 0)

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That is, the new region in the u-v domain is a rectangle where \frac{-1}{15}\leq u \leq \frac{1}{15}, 0\leq v \leq \frac{2}{15}.

We will calculate the jacobian of the change variables. That is

\left |\begin{matrix} \frac{du}{dx}& \frac{du}{dy}\\ \frac{dv}{dx}& \frac{dv}{dy}\end{matrix}\right| (we are calculating the determinant of this matrix). The matrix is

\left |\begin{matrix} \frac{1}{75}& \frac{-1}{75}\\ \frac{4}{75}& \frac{1}{75}\end{matrix}\right|=(\frac{1}{75^2})(1+4) = \frac{1}{15\cdot 75} (the in-between calculations are omitted).

We will, finally, do the calculations.

Recall that

15x+15y = 15(15u+15v) + 15(-60u+15v) = (15^2-15\cdot 60 )u+2\cdot 15^2v = 15^2(-3)u+2\cdot 15^2 v

We will use the change of variables theorem. So,

\int_R 15x+15y dA = \int_{\frac{-1}{15}}^{\frac{1}{15}}\int_{0}^{\frac{2}{15}} 15^2(-3)u+2\cdot 15^2 v \cdot (\frac{1}{15^2\cdot 5}) dv du = \int_{\frac{-1}{15}}^{\frac{1}{15}}\int_{0}^{\frac{2}{15}}\frac{-3}{5}u+\frac{2}{5}v dvdu

This si because we are expressing the original integral in the new variables. We must multiply by the jacobian to guarantee that the change of variables doesn't affect the value of the integral. Then,

\int_{\frac{-1}{15}}^{\frac{1}{15}}\int_{0}^{\frac{2}{15}}\frac{-3}{5}u+\frac{2}{5}v dvdu = \int_{\frac{-1}{15}}^{\frac{1}{15}}\frac{-3}{5}u\cdot \frac{2}{15} + \frac{2}{5}\cdot \left.\frac{v^2}{2}\right|_{0}^{\frac{2}{15}}du = \frac{-3}{5}\left.\frac{u^2}{2}\right|_{\frac{-1}{15}}^{\frac{1}{15}}\cdot \frac{2}{15} + \frac{2}{5}\cdot \left.\frac{v^2}{2}\right|_{0}^{\frac{2}{15}} = \frac{8}{16875}

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podryga [215]

Answer:

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Step-by-step explanation:

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d) This option is also wrong because 5.2 must be the third number in the list not the first.

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Answer:

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General Formulas and Concepts:

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Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² - 3x - 2

f(x + 3) is x = x + 3

<u>Step 2: Find</u>

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