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3 years ago

Congruent Triangles and Proofs Given: JK bisects

Mathematics

1 answer:

Nikitich [7]3 years ago

7 0

Answer:

Step-by-step explanation:

1S. JM bisects ∠ KJL and ∠JMK ≅ ∠JML

1R. Given

2S. ∠KJM ≅ ∠LJM

2R. Angle bisectors form ≅ ∠s

3S. JM≅JM

3R. Reflexive Propriety ( segment is ≅ with itself)

4S. ΔJMK ≅ΔJML

4R. ASA theorem of congruency

5S. JK≅JL

5R. Coresponding parts of congruent Δs are congruent (CPCTC)

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The value of a piece of equipment is decreasing at a rate of 7,5% yearly. If the equipment

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Answer:

y=930 x 075^x

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3 years ago

Janine's dog weighs three pounds less than twice the weight of Wanda's dog, d. Which

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3 years ago

One factor of the function f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5) Describe how to find the x-intercepts and the y-intercept o

pickupchik [31]

Answer:

x-intercept(s): (−1.9900717, 0)

y-intercept(s): (0, 52.5)

Step-by-step explanation:

To find the x-intercept, substitute in $0$ for $y$ and solve for $x$ . To find the y-intercept, substitute in $0$ for $x$ and solve for $y$ .

$f(x)=y$

$(x)=x$

<u>x-intercept</u>

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5$

$=\bold{0}=x^3-8x^2+17x-10.5\left(x-5\right)$

$=0\cdot \:10=x^3\cdot \:10-8x^2\cdot \:10+17x\cdot \:10-10.5\left(x-5\right)\cdot \:10$

$=0=10x^3-80x^2+170x-105\left(x-5\right)$

$=0=10x^3-80x^2+65x+525$

$=10x^3-80x^2+65x+525=0$

$=10x^2-99.90071\dots x+263.80959\dots \approx \:0$

$\bold{x\approx \:-1.99007\dots}$

<u>y-intercept</u>

$f(x) = x ^ 3 - 8x ^ 2 + 17x - 10.5(x - 5$

$=y=\bold{0}^3-8(\bold{0})^2+17(\bold{0})-10.5\left(\bold{0}-5\right)$

$=y=0-8\cdot \:0+17\left(0\right)-10.5\left(0-5\right)$

$=y=0-8\cdot \:0+17\cdot \:0-10.5\left(0-5\right)$

$=y=0-0+0-\left(-52.5\right)$

$=0-0+0+52.5$

$\bold{y=52.5}$

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2 years ago

If an angle is 167°,then it is obtuse

sattari [20]

If an angle is 167 degrees, it is an obtuse angle because, it's greater than a 90 degree angle. (right angle) Let me give you some details on why 167 degrees is an obtuse angle. You probably don't remember from your math classes in the past but, when they give you an angle value and they want to know if it's either a right angle, an acute angle, or an obtuse angle, you figure it out by doing these steps: 1. You take a protractor (it's kinda like a ruler, but it measures angles) and measure the angle given to find out the size of it in degrees. 2. Once you have the measured the angle and found the angle's size in degrees, ask yourself whether it's greater than 90 or less than 90. You want to ask yourself whether the angle measurement you found is greater than 90 or less than 90 because, if the size of the angle is exactly 90 degrees, than the angle you measured is a right angle. Now if the angle is greater than 90 (91 and Higher), then you know the angle is an obtuse angle. Which means by process of emulation, that if the angle you found is less than 90 (1-89), than the angle is an acute angle. And that's why a 167 degree angle is an obtuse angle Did that help you with your question or do you need just a little bit more understanding?

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3 years ago