Answer:
Do not see a picture or graph but suspect it would show the golf ball falling faster and striking the ground slightly before the soccer ball.
Probably D: Soccer ball was affected by air resistance more than the golf ball.
Explanation:
Even though heavier, friction loss of the greater surface area soccer ball will counter pull of gravity more than the compact golf ball.
In a vacuum, (no friction) both objects fall at the same rate regardless of mass.
Nichrome wire. That's the stuff that toasters are made from. The resistance is pretty high, considering the diameter. 1 meter is at about the same guage as that listed below for copper is about 96 ohms.
Most of the time you are trying to use wire with the least resistance.
A meter of copper has a listed resistance of 0.024 ohms / meter. The wire is a 19 guage wire which makes it pretty thin.
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I'm not sure what you are asking. If want the resistance of something in terms of what would increase the resistance of the same material for both calculations then
Rule 1: It you decrease the wire diameter, you increase the resistance
Rule 2: If you increase the length of the wire, you increase the resistance.
Both rules assume you are using something like copper.
Answer:
359 g Mn
General Formulas and Concepts:
- Dimensional Analysis
- Reading the Periodic Table of Elements
Explanation:
<u>Step 1: Define</u>
6.53 mol Mn
<u>Step 2: Find conversion</u>
1 mol Mn = 54.94 g Mn
<u>Step 3: Dimensional Analysis</u>
<u />
= 358.758 g Mn
<u>Step 4: Simplify</u>
<em>We are given 3 sig figs.</em>
358.758 g Mn ≈ 359 g Mn
Answer:
Explanation:
As we know that the formula of range is given as
now we know that
maximum value of the range of the projectile is given as
now we need to find such angles for which the range is half the maximum value
so we will have
Answer:
A)5524J,
B) 29.2Nm
Explanation:
This question can be treated using work- energy theorem
Work= change in Kinectic energy
W= Δ KE
Work= difference between the final Kinectic energy and intial Kinectic energy.
We know that
Kinectic energy= 1/2 mv^2 .............eqn(1)
This can be written in term of angular velocity, as
KE= 1/2 I
