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N76 [4]
2 years ago
9

true or false each human somatic cell contains two copies of each chromosomes for a total of 23 chromosomes

Biology
2 answers:
r-ruslan [8.4K]2 years ago
6 0
I think the answer is false
baherus [9]2 years ago
3 0

Answer:

I'm pretty sure it might be false

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In man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-wooly ha
Brut [27]

Answer:

Total four genotypes and its frequency  

SsWw – 4/16

ssWw- 4/16

Ssww - 4/16

ssww - 4/16

Phenotype –  

SsWw – Heterozygous  Spotted skin and heterozygous wooled hair

ssWw  - Homozygous non-spotted skin and heterozygous wooled hair

Ssww  -  Heterozygous  Spotted skin and Homozygous non -wooled hair

ssww  - Homozygous non-spotted skin  and Homozygous non -wooled hair

Explanation:

Given -

Allele for spotted skin is "S"

Allele for non-spotted skin is "s"

Allele for Wooly hair is "W"

Allele for non-wooly hair is "w"

Allele "S" is dominant over "s"

And Allele "W" is dominant over "w"

Cross is carried out between heterozygous spotted, non-wooly man and heterozygous wooly-haired, non-spotted woman

Genotype of heterozygous spotted, non-wooly man - Ssww

Genotype of  heterozygous wooly-haired, non-spotted woman - ssWw

Ssww * ssWw

Sw         Sw         sw         sw

sW SsWw SsWw ssWw ssWw

sw Ssww Ssww ssww ssww

sW SsWw SsWw ssWw ssWw

sw Ssww Ssww ssww ssww

Total four genotypes and its frequency  

SsWw – 4/16

ssWw- 4/16

Ssww - 4/16

ssww - 4/16

Phenotype –  

SsWw – Heterozygous  Spotted skin and heterozygous wooled hair

ssWw  - Homozygous non-spotted skin and heterozygous wooled hair

Ssww  -  Heterozygous  Spotted skin and Homozygous non -wooled hair

ssww  - Homozygous non-spotted skin  and Homozygous non -wooled hair

8 0
3 years ago
Is oxygen necessary for the production of apt in your cells?
gizmo_the_mogwai [7]
Yes it is necessary for the production of apt in your cells because apt needs oxygen to form correctly.
7 0
3 years ago
the genes stc1 and stc2, which share a common ancestor, are found in both zebrafish and humans. all four stc genes display simil
Temka [501]

Based on these facts, we can state that the genes of the two organisms had a eukaryotic origin.

We can arrive at this answer because:

  • Despite having exons, prokaryotes do not have introns in their genomes.
  • This means that if two organisms have the same sequence of introns and exons, they have a common ancestor, in addition to having their genes originated in a eukaryotic organism, which explains the sequence of introns.

This means that the genetic expression of these two organisms has similarities, even if they are organisms with different biological processes.

More information:

brainly.com/question/3641593?referrer=searchResults

5 0
2 years ago
Cross a heterozygous brown, short hair with homozygous brown, hybrid long haired dog
Alexxandr [17]
Heterozygous brown short= Bs
homozygous brown long=BL
      B             s
 B   [         ]          ]
      [_BB_]__Bs_]
      [         ]         ]
 L   [_BL_]_Ls_]
50% %50
3 0
3 years ago
Read 2 more answers
What is homozygous?
arsen [322]

Answer:

the correct the answer is a

7 0
3 years ago
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