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tresset_1 [31]
3 years ago
6

An axon can alter the speed or magnitude of its action potentials Select one True False

Biology
2 answers:
zlopas [31]3 years ago
6 0

Answer:

TRUE

Size. Action potentials travel down neuronal axons in an ion cascade. ... This continues down the axon and creates the action potential. Larger diameter axons have a higher conduction velocity, which means they are able to send signals faster.

Gemiola [76]3 years ago
5 0

True, if possible can u maybe mark me as brainliest? ^w^

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3. Explain how it is possible to have thousands of different proteins when there are only 20 different amino acids.
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Amino acids create protiens, endless possibilities of combinations of amino acids result in a wide variety of proteins
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The most plausible hypothesis to explain why species richness is higher in tropical than in temperate regions is that
qwelly [4]
The most plausible hypothesis is: Tropical regions generally have more available water and higher levels of solar radiation. They also have very high rates of immigration and very low rates of extinction.

explanation:
Water is essential for an abundance of life, and sunlight is the means by which the whole food chain receives energy. Plants convert the sunlight into food, herbivores eat them, and other animals eat herbivores.

Hope this helps, and muchas luck on your biology.
7 0
3 years ago
प्र.नं. १ समूह'क' मा दिइएकोश
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plz attach photo .....

Explanation:

फोटो हाले बल्ला बुझिन्छ । यसरी त के के हो के के।।।।

6 0
3 years ago
Read 2 more answers
Based on the cladogram, if moths undergo complete metamorphosis, we would MOST LIKELY infer that
Salsk061 [2.6K]
A.) butterflies and flies do as well
8 0
3 years ago
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22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit
mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square (X^2):

X^2  =  \frac{(O - E)^2}{E} where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The X^2 is calculated thus:

Phenotype            O               E                             X^2

  1                          88            164.81            \frac{(88 - 164.81)^2}{164.81} = 35.80

  2                          62             54.94            \frac{(62 - 54.94)^2}{54.94} = 0.91

  3                           62             54.94              \frac{(62 - 54.94)^2}{54.94} = 0.91

  4                            81              18.31               \frac{(81 - 18.31)^2}{18.31} = 214.64

Total X^2 = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

X^2 tabulated  = 7.815

<em>The calculated </em>X^2<em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently.        </em>

4 0
3 years ago
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