What is the slope of the line through points (0,6) and (5,-4)
1 answer:
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This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
Answer:
confidence interval = ( -0.38 , 0.08 )
Step-by-step explanation:
Given data :
n1 = 55 , n2 = 60 ,
Let P1 ( proportion of SUV sales at store A ) = 30 / 55 = 0.55
P2 ( sample proportion of SUV sales at store B ) = 42/60 = 0.70
The Z-value at 99% confidence Interval = 2.58
<u>Determine the 99% confidence interval for difference in proportion</u>
applying the formula below
( P1 - P2 ) ± Z (
Input values above into equation
confidence interval = ( -0.38 , 0.08 )