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3 years ago

Simplify and determine the coefficient of (- 2/3x)(-x)(3y)(-2x)

Mathematics

1 answer:

Mashutka [201]3 years ago

8 0

4x^2y the coefficient in 4

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Use the quadratic formula to solve the equation. -2x^2-x+7=0.

Furkat [3]

<span>-2x^2-x+7=0
Variable with the highest degree's (exponent) constant, -2 is a, next variable's constant, -1 is b, the constant or number without a variable, 7 is c

using substitution put the numbers into the formula
</span>(-b±√(b^(2)-4ac))/(a^(2))

(-(-1)±√((-1)^(2)-4(-2)(7))/((-2)^(2)) simplify

(1±√(1+56))/4

1±√(57)/4 is your answer

8 0

3 years ago

Solve for x -3 + x <br> = - 38

fiasKO [112]

x-3+x=-38

2x-3=-38

2x=3-38=-35

x=-35/2=-17.5

3 0

3 years ago

Read 2 more answers

A figure is composed of two half-circles.

posledela

Answer:

The answer is C, 220 units.

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%3Cbr%3E%0Ay%3D%20x%5E%7B2%7D%20-9" id="TexFormula1" title="&#10;y= x^{2} -9" alt="&#1

svp [43]

Simple...

y= $x^{2} -9$

$y= x^{2} -9$

It's quite easy to see $x^{2} = x^{2}$

Thus, any value of x makes the equation true.

Thus, your answer.

7 0

3 years ago

Answer Question number 5 <br> Plzzzzzz

loris [4]

Answer:

Step-by-step explanation:

a = -4/3

d= -1 +4/3 =1/3

last term = 4 1/3 = 13/3

nth term = a +(n-1)d

$\frac{-4}{3}+(n-1)*\frac{1}{3}=\frac{13}{3}\\\\(n-1)*\frac{1}{3}=\frac{13}{3}-\frac{-4}{3}\\\\(n-1)*\frac{1}{3}=\frac{13+4}{3}\\\\(n-1)*\frac{1}{3}=\frac{17}{3}\\\\n-1=\frac{17}{3}*\frac{3}{1}\\\\n-1=17\\\\n=17+1=18$

Middle terms are 9the term and 10th term

$t_{9}=\frac{-4}{3}+8*\frac{1}{3}=\frac{-4}{3}+\frac{8}{3}=\frac{4}{3}\\\\t_{10}=\frac{-4}{3}+9*\frac{1}{3}=\frac{-4}{3}+\frac{9}{3}=\frac{5}{3}\\\\ t_{9}+t_{10}=\frac{4}{3}+\frac{5}{3}=\frac{9}{3}=3\\\\t_{9}+t_{10}=3$

3 0

3 years ago