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2 years ago

Convert 13 to fifths. Write your answer as a fraction.

Mathematics

1 answer:

Zina [86]2 years ago

4 0

Answer:

65/5

Step-by-step explanation:

You just need to multiply 13 by 5.

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How can I write repeating decimals

chubhunter [2.5K]

A repeating decimal can be written like this

4 0

3 years ago

The cost of a regular price ticket to a saint Louis cardinals baseball game was $60. During the World Series, the price increase

Ray Of Light [21]

So regular is 60
increased by 2/5 or +2/5
so
60+(60(2/5))=x
60 times 2/5=120/5=24
60+24=84

the fans paied $84

4 0

3 years ago

Read 2 more answers

What is the answer?

zepelin [54]

Answer:

x = 110° ; y = 49°

Step-by-step explanation:

m∠ABD = m∠ADB = 35° ⇒ x = 180° - 2 × 35° = 110°

m∠CDB = m∠CBD = 2y ⇒ y = (180° - 82°) ÷ 2 = 49°

3 0

3 years ago

How do i find the slope- 20 points answer! [imagine below included!]

Dafna11 [192]

Answer:

3/3 = 1

Step-by-step explanation:

The slope formula is..

Pick two formulas. Let's do (-5, -2) and (-2, 1)

x1 y1 x2 y2

(-5, -2) (-2, 1)

$\frac{1-(-2)}{-2-(-5)}$ = $\frac{3}{3}$ = 1

It'll work the same thing for (-2, 1) and (1,4)...

3/3 or 1 is a pattern between the points.

5 0

2 years ago

Which of the following represent the values of x, y, and z.

Paraphin [41]

Answer:

Part 1) $z=4\sqrt{3}\ units$

Part 2) $y=4\sqrt{2}\ units$

Part 3) $x=4\sqrt{6}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

Find the value of z

In the right triangle DBC

$cos(C)=\frac{4}{z}$ ----> equation A

In the right triangle ABC

$cos(C)=\frac{z}{12}$ ----> equation B

equate equation A and equation B

$\frac{4}{z}=\frac{z}{12}$

$z^{2}=48$

$z=4\sqrt{3}\ units$

step 2

In the right triangle DBC

Applying the Pythagoras Theorem

$z^{2}=y^{2}+4^{2}$

we have

$z=4\sqrt{3}\ units$

substitute

$(4\sqrt{3})^{2}=y^{2}+4^{2}$

$48=y^{2}+16$

$y^{2}=48-16$

$y^{2}=32$

$y=4\sqrt{2}\ units$

step 3

Find the value of x

In the right triangle ABC

Applying the Pythagoras Theorem

$12^{2}=x^{2}+z^{2}$

we have

$z=4\sqrt{3}\ units$

substitute

$12^{2}=x^{2}+(4\sqrt{3})^{2}$

$144=x^{2}+48$

$x^{2}=144-48$

$x^{2}=96$

$x=4\sqrt{6}\ units$

6 0

3 years ago