Answer:50212.5
Step-by-step explanation:
Answer:
the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
Step-by-step explanation:
From the five randomly selected students ; 160, 175, 163, 149, 153
mean average of the students = 160+175+163+149+153/5
= mean = x-bar = 800/5
mean x-bar = 160
from probability distribution, P(x-bar > 160) = P[ x-bar - miu / SD > 160 -150.8 /3.94]
P( Z>2.34) = from normal Z-distribution table
= 0.0096419
= 0.0096
hence the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
where SD = standard deviation = 3.94 and Miu = 150.8
I am pretty sure it’s the first one
Answer:
Step-by-step explanation:
P=2l+2w
28=2l+2w
2l=2w-28
l = (2w-28)/2
l =2(w-14)/2
l = w-14
1.) 11 - 3 4/12
2.) 11 - 3 1/3
3.) 11/1 - 3 1/3
4.) 33/3 - 10/3
5.) 23/3 or 7.7 or 7 2/3 is your answer, depending on how you want it
