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fiasKO [112]
3 years ago
10

What is the product of (3+4i) and its conjugate?

Mathematics
1 answer:
Degger [83]3 years ago
7 0
A is the correct answer
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Solve the system of elimination -2x+2y+3z=0 -2x-y+z=-3 2x+3y+3z=5
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Answer:

x = 1 , y = 1 and z = 0

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-2x+2y+3z=0    ------(1)

-2x-y+z=-3     --------(2)

2x+3y+3z=5    ---------(3)

<u>To find the values of x,y and z</u>

(3) - (2)⇒ 2y + 4z = 2

y + 2z = 1   --------(4)

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(5) - (4)⇒ 2y = 2

y = 1

Substituting the value of y in (4) we get z =0

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Therefore x = 1 , y = 1 and z = 0

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3 years ago
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