A side view of a desk telephone is shown below. which of the following is closest to the value of x
2 answers:
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Using the simple interest formula, it is found that the APR for the loan is of 4.472%.
<h3>What is the simple interest formula and when it is used?</h3>Simple interest is used when there is a single compounding per time period.
The amount of money after t years in is modeled by:
In which:
- A(0) is the initial amount.
- r is the interest rate, as a decimal.
The parameters for this problem are:
A(t) = 6 x 511.18 = 3067.08, A(0) = 3000, t = 0.5.
We solve the equation for r to find the APR.
1 + 0.5r = 1.02236
r = (1.02236 - 1)/0.5
r = 0.04472.
More can be learned about simple interest at brainly.com/question/25296782
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Answer and explanation:
To find : List the sample space and tell whether you think the events are equally likely ?
Solution :
a) Toss 2 coins; record the order of heads and tails.
Let H is getting head and t is getting tail.
When two coins are tossed the sample space is {HH,HT,TH,TT}.
Total number of outcome = 4
As the outcome HT is different from TH. Each outcome is unique.
Events are equally likely since their probabilities are same.
b) A family has 3 children; record the number of boys.
Let B denote boy and G denote girl.
If there are 3 children then the sample space is
{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}
The possible number of boys are 0,1,2 and 3.
Number of boys Favorable outcome Probability
0 GGG
1 GGB,GBG,BGG
2 GBB,BGB,BBG
3 BBB
Since the probabilities are not equal the events are not equally likely.
c) Flip a coin until you get a head or 3 consecutive tails; record each flip.
Getting a head in a trial is dependent on the previous toss.
Similarly getting 3 consecutive tails also dependent on previous toss.
Hence, the probabilities cannot be equal and events cannot be equally likely.
d) Roll two dice; record the larger number
The sample space of rolling two dice is
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Now we form a table that the number of time each number occurs as maximum number then we find probability,
Highest number Number of times Probability
1 1
2 3
3 5
4 7
5 9
6 11
Since the probabilities are not the same the events are not equally likely.