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3 years ago

Without graphing, determine whether the function y = ( 5 . 2 )^x represents exponential growth or exponential decay.

1 answer:

7 0

exponential growth is your answer. If it is not a negative then it wont be exponential decay. if it is a positive then it is growth

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Problem solving with inequalities

anzhelika [568]

Option D:

15c ≤ 200

Solution:

Let c be the number of cases of tea bags.

Cost of each tea bag = 15 gold coins

Total gold coins Mad have = 200

Set up an inequality:

Cost of c tea bags = 15 × c = 15c

Mad can buy tea bags at most 200 gold coins.

(At most 200 means 200 is the greater value)

15 × c ≤ 200

15c ≤ 200

Hence option D is the correct answer.

8 0

3 years ago

Geometry question on finding x.

Dmitrij [34]

Answer:

$x =63^o$

Step-by-step explanation:

Given :-

$\text{ $\overline{MN} $ and $\overline{ML}$ are tangents .}$

We know that the tangents are perpendicular to the radius at the point of contact . And here OLMN is a quadrilateral. Also we know that , the angle sum property a triangle is 360° .

According to question :-

$\implies x + 117^o + 90^o +90^o = 360^o \\\\\implies x + 297^o = 360^o \\\\\implies x = 360^o - 297^o \\\\\implies x = 63^o$

Hence the value of x is 63° .

6 0

2 years ago

A sequence can be generated ny using (look at image below)? someone please help:)

mixer [17]

Answer:

6, 24, 96, 384

Step-by-step explanation:

a₁ = 6

a₂ = 4 x a₁ = 4 x 6 = 24

a₃ = 4 x a₂ = 4 x 24 = 96

a₄ = 4 x a₃ = 4 x 96 = 384

8 0

3 years ago

The shape of the cylinder

Oxana [17]

The cylinder is 17cm Bc it go up not down

3 0

2 years ago

Marie will earn $15 per hour at a new job. During training, she will earn $10 per hour. What percent of Marie’s regular hourly r

Hitman42 [59]

Answer: 66.67%

Step-by-step explanation:

Given: The amount Marie will earn at a new job = $15 per hour

The amount she will earn during the training = $10 per hour

The percent of Marie’s regular hourly rate she will earn during training is given by :-

$P=\frac{\text{Rate of amount she earn in training }}{\text{Rate of amount she earn at new job }}\times100\\\\\Rightarrow\ P=\frac{10}{15}\times100\\\\\Rightarrow\ P=66.66666\%\approx66.67\%$

4 0

2 years ago