Answer:
the answer is 3
Step-by-step explanation:
(-5x-3)(-5x+3)=(5x)^2 - (3)^2
A difference of squares is the difference of two squared terms.
We have
a^2 - b^2
We can factorize the difference of squared terms like this:
a^2-b^2 = (a+b)(a-b)
We have (-5x-3)(-5x+3)
Lets prove it:
(-5x-3)(-5x+3) = (-5x*-5x)+(-5x*3)+(-3*-5x)+(-3*3)
(-5x-3)(-5x+3) = 25x^2+(-15x)+(15x)+(-9)
(-5x-3)(-5x+3) = 25x^2-15x+15x-9
(-5x-3)(-5x+3) = 25x^2-9
(-5x-3)(-5x+3) = (5x)^2 - (3)^2
Answer:
3
Step-by-step explanation:
In order to do this equation, your first step is to use the Order of Operations, or PEMDAS, which means that you multiply (M) two times two first before subtracting the equation (S). 2 times 2 is 4. 4 - 1 = 3. Hope I helped! :)
Answer:
9, 9.5,9.551,9.59,9.626,9.66,9.662
Step-by-step explanation:
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Step-by-step explanation:
-x, -(x+1)
-x-(x+1)=10506
x^2+x-10506=0