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3 years ago

Why is the sum of a rational number and a irrational number always irrational

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

5 0

Answer:

A rational number is a number able to be put into a fraction, an irrational number is not able to be. Therefore, when adding the two, the rational and the irrational will be irrational. For example, 2 is a rational number, and 1.8903 is irrational. If you add the two, you will get 3.18903, which is unable to be put into a fraction.

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1 1/45 into a improper fraction

balu736 [363]

46/45. do u know how 2 do it? hope u do

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3 years ago

Which equation involves a prime quadratic and cannot be solved by factoring? A. x2 + 5x − 4 = 0 B. x2 − x − 6 = 0 C. x2 + 3x − 4

Damm [24]

Answer:

Option A

Step-by-step explanation:

We can try to factorize all the options one by one.

For A:

$x^{2} +5x-4\\=> x^{2}+4x+x-4\\=>x(x+4)+1(x-4)$

We can see that the quadratic expression cannot be solved by factorization as the factors at the end of factorization are not equal in both brackets. So Option A is the correct answer for the given question.

Moreover we can also note that all the other quadratic expressions can be factorized ..

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3 years ago

What is 608 + 17.25?

adelina 88 [10]

Answer:

625.25

Step-by-step explanation:

the answer is 625.25

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2 years ago

Read 2 more answers

A jar holds 128 fluid ounces of juice. The label says the jar has 16 servings. How many fluid ounces are needed for 80 servings?

Bumek [7]

There are 16 servings for each 128 fluid ounces of juice.

Divide 80 servings by 16 servings, and 5 should be the quotient. Therefore, there are 5 jars of juice. Multiply 128 by 5 since 128 fluid ounces are in one jar. The answer should be 640 fluid ounces.

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3 years ago

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PLEASEEEEE HELP ME <br> yes, hl<br> yes, asa <br> no not enough info <br> yes, sas

podryga [215]

Answer:

a) Yes, HL

Step-by-step explanation:

$We\ know\ that:\\Both\ triangles\ are\ right\ triangles. (90\ degree)\\They\ share\ a\ common\ side.\\They\ have\ their\ hypotenuses\ corresponding.\\Hence,\\Through\ HL(If\ the\ hypotenuse\ and\ any\ leg\ of\ the\ triangles\ are\ corresponding,$ $then,\ the\ two\ triangles\ are\ congruent.)$

$We\ can\ hence,\ conclude\ that\ the\ given\ triangles\ are\ congruent.$

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3 years ago