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Lostsunrise [7]

3 years ago

11

A student loan needs to be paid off beginning the first year after graduation. Beginning at Year 1, there is $52,000 remaining t

o be paid. The graduate makes regular payments of $8,000 each year. The graph shows the sequence. f(x)=?

1 answer:

Rom4ik [11]3 years ago

5 0

Answer:

The equation is: $f(x) = 52000 - 8000x$

Step-by-step explanation:

Given

Initial = 52000

Rate = 8000 each year

Required

Determine the equation of the graph

The equation can be determined using.

$Amount = Initial - Rate* Years$

We used minus (-) because, the amount reduces as the student pays.

Let

$y = Amount$

$x = Years$

So, we have:

$y = Initial - Rate * x$

Substitute values for Initial and Rate

$y = 52000 - 8000 * x$

$y = 52000 - 8000x$

Express as a function:

$f(x) = 52000 - 8000x$

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10:4 is the ratio you're looking for.

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melisa1 [442]

Answer:

B = 781.347

Step-by-step explanation:

Since we already have an equation just plug in terms where needed.

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$B=4131^{\frac{4}{5}}$

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3 years ago

What should be subtracted from the product of<br>3/7 and 2/5 to get -4/35?

bonufazy [111]

$\implies {\pink {\boxed {\boxed {\purple {\sf { \: x = \frac{2}{7}}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

Let $x$ be the unknown number.

As per the question, we have

$\: ( \frac{3}{7} \times \frac{2}{5} ) - x = \frac{ - 4}{35}$

➺ $\: \frac{6}{35} - x = \frac{ - 4}{35}$

➺ $\: - x = \frac{ - 4}{35} - \frac{6}{35}$

➺ $\: - x = \frac{ - 4 - 6}{35}$

➺ $\: - x = \frac{ - 10}{35}$

➺ $\: x = \frac{2}{7}$

Therefore, $\frac{2}{7}$ should be subtracted from the product of $\frac{3}{7}$ and $\frac{2}{5}$ to get $\frac{ - 4}{35}$ .

$\large\mathfrak{{\pmb{\underline{\orange{To\:verify}}{\orange{:}}}}}$

$\: ( \frac{3}{7} \times \frac{2}{5} ) - x = \frac{ - 4}{35}$

➼ $\: ( \frac{6}{35} ) - \frac{2}{7} = \frac{ - 4}{35}$

➼ $\: \frac{6}{35} - \frac{2 \times 5}{7 \times 5} = \frac{ - 4}{35}$

➼ $\: \frac{6 - 10}{35} = \frac{ - 4}{35}$

➼ $\: \frac{ - 4}{35} = \frac{ - 4}{35}$

➼ $\: L.H.S.=R. H. S$

$\sf\purple{Hence\:verified. }$

$\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{☂}}}}}$

3 0

3 years ago

Simplify tan theta times sin theta

daser333 [38]

Answer:

tan θ × sin θ

From trigonometric identities

$\tan(θ) = \frac{ \sin(θ) }{ \cos(θ) }$

So we have

$\frac{ \sin(θ) }{ \cos(θ) } \times \sin(θ)$

We have the final answer as

$\frac{ \sin(θ)^{2} }{ \cos(θ) }$

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7 0

4 years ago

On a coordinate plane, point B(–6, 1) is translated to B prime(–3, –2). Indira uses these steps to find a rule to describe the t

nasty-shy [4]

Answer:

Indira should have written the equations Negative 6 + a = negative 3 and 1 + b = negative 2 in Step 2.

Step-by-step explanation:

Point B(-6, 1) to B'(-3, -2)

Steps to achieve B"

-6+a= -3 ⇒ a= -3+6= 3

1+b= -2 ⇒ b= -2-1= -3

-----------------

Step 1 Substitute the original coordinates and the translated coordinates into (x, y) right-arrow (x + a, y + b): B (negative 6, 1) right-arrow B prime (negative 6 + a, 1 + b) = B prime (negative 3, negative 2)

Step 2 Write two equations: Negative 6 + a = negative 2. 1 + b = negative 3.
wrong step

Step 3 Solve each equation: Negative 6 + a = negative 2. a = negative 2 + 6. a = 4. 1 + b = 3. b = negative 3 minus 1. b = negative 4.

Step 4 Write the translation rule: (x, y) right-arrow (x + 4, y minus 4)

----------------

Indira should have written the equations Negative 6 + a = negative 3 and 1 + b = negative 2 in Step 2.

3 0

3 years ago

Read 2 more answers