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andrew-mc [135]

3 years ago

8

A magazine advertises that a subscription price of $29.99 for (12 issues) represents a savings of 70% from the newsstand price.

What is the price of 1 issue at the newsstand?

1 answer:

devlian [24]3 years ago

4 0

It would be bout 2.50 for on issue. Hope that helped

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3) The Buendorf family has agreed to let their children get some animals. The kids said they

bezimeni [28]

Answer:

The possible number of goats is 6 and the possible number of chicken is 24

Step-by-step explanation:

Let

chicken=c

Goat=g

the number of chickens could be four times the number of goats

c=4g

Total number of animals=30

c+g=30

Recall, c=4g

So,

c+g=30

4g+g=30

5g=30

Divide both sides by 5

5g/5=30/5

g=6

Recall,

c+g=30

c+6=30

c=30-6

=24

c=24

The possible number of goats is 6 and the possible number of chicken is 24 making a total of 30 animals

5 0

3 years ago

Which equation should be used to find the volume of the figure?

DaniilM [7]

Answer:

Given that

1

John can run 100 meters dash in 16 --------- seconds .

5

Savanna 's time is 19.8 seconds .

Here we have John time in mixed fraction and Savanna's time in decimal .

Converting mixed fraction into improper .

1 16 * 5 + 1 80 + 1 81

16 -------- = --------------------------- = -------------- = - -----------

5 5 5 5

Thus we got John time as 81 /5 seconds .

Converting Savanna's time in fraction , we get

19 8

---------- seconds .

10

We have two fractions with different denominator .

One is having denominator 5 and another is having denominator 10 .

We need to make the denominator same of both the fraction .

We need to make denominator 10 .

Multiply John fraction by 2 in both numerator and denominator by 2 to make denominator 10 .

81 * 2 162

---------- = ------------ seconds .

5 * 2 10

John is taking less time than Savanna . Thus John is faster .

Difference

198 162 36

------- - ------- = ------- seconds

10 10 10

Thus John is faster by (36/10 ) seconds = 3.6 seconds.

Step-by-step explanation:

Given that

1

John can run 100 meters dash in 16 --------- seconds .

5

Savanna 's time is 19.8 seconds .

Here we have John time in mixed fraction and Savanna's time in decimal .

Converting mixed fraction into improper .

1 16 * 5 + 1 80 + 1 81

16 -------- = --------------------------- = -------------- = - -----------

5 5 5 5

Thus we got John time as 81 /5 seconds .

Converting Savanna's time in fraction , we get

19 8

---------- seconds .

10

We have two fractions with different denominator .

One is having denominator 5 and another is having denominator 10 .

We need to make the denominator same of both the fraction .

We need to make denominator 10 .

Multiply John fraction by 2 in both numerator and denominator by 2 to make denominator 10 .

81 * 2 162

---------- = ------------ seconds .

5 * 2 10

John is taking less time than Savanna . Thus John is faster .

Difference

198 162 36

------- - ------- = ------- seconds

10 10 10

Thus John is faster by (36/10 ) seconds = 3.6 seconds.

4 0

2 years ago

Twenty percent multiply by x is what

elena-s [515]

Well I need more details for x can you screenshot? It’s usually x*0.20 but I need more details to help you

7 0

2 years ago

PLEASE HELP ITS DUE IN LIKE30 min !!!!!!!!!Give the following functions f(x) and g(x),solve (f/g) (-5) and select the correct an

Bingel [31]

Answer:

The answer is -32

Step-by-step explanation:

g(-5) = (-5)-1= -6

f(-6) = 2(-6)-20

f(-6) = -12-20

-32

6 0

3 years ago

Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)

GarryVolchara [31]

<u>Question 6</u>

1) $\overline{AB} \cong \overline{BD}$ , $\overline{CD} \perp \overline{BD}$ , O is the midpoint of $\overline{BD}$ , $\overline{AB} \cong \overline{CD}$ (given)

2) $\angle ABO, \angle ODC$ are right angles (perpendicular lines form right angles)

3) $\triangle ABO, \triangle CDO$ are right triangles (a triangle with a right angle is a right triangle)

4) $\overline{BO} \cong \overline{OD}$ (a midpoint splits a segment into two congruent parts)

5) $\triangle ABO \cong \triangle CDO$ (LL)

<u>Question 7</u>

1) $\angle ADC, \angle BDC$ are right angles), $\overline{AD} \cong \overline{BD}$

2) $\overline{CD} \cong \overline{CD}$ (reflexive property)

3) $\triangle CDA, \triangle CDB$ are right triangles (a triangle with a right angle is a right triangle)

4) $\triangle ADC \cong \triangle BDC$ (LL)

5) $\overline{AC} \cong \overline{BC}$ (CPCTC)

<u>Question 8</u>

1) $\overline{CD} \perp \overline{AB}$ , point D bisects $\overline{AB}$ (given)

2) $\angle CDA, \angle CDB$ are right angles (perpendicular lines form right angles)

3) $\triangle CDA, \triangle CDB$ are right triangles (a triangle with a right angle is a right triangle)

4) $\overline{AD} \cong \overline{DB}$ (definition of a bisector)

5) $\overline{CD} \cong \overline{CD}$ (reflexive property)

6) $\triangle ADC \cong \triangle BDC$ (LL)

7) $\angle ACD \cong \angle BCD$ (CPCTC)

8 0

1 year ago