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tiny-mole [99]
2 years ago
7

The temperature in Berlin is -7 °C and the temperature in Istanbul is -3 °C.

Mathematics
1 answer:
Orlov [11]2 years ago
5 0

Answer:

(a) is 4*C and (B) is 16*C

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What is 2∙ 2∙ 2∙ 2∙ 2∙ 2∙ 2∙ 2∙ 2 in exponential form?
Lubov Fominskaja [6]

Answer:

2^9

Step-by-step explanation:

Since there are nine 2s being multiplied by each other, we can represent this as 2^9.

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Graph ​y=−4/7x+1​. do this math
Fofino [41]

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Use demos or a graphing calc.

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Can ya help me please. i need it
ankoles [38]

Answer: Since I don't really understand the question it's asking, I would assume that the answer for no. 1 is Swiss, and the answer for no. 2 is Cheddar. I know it's not completely an accurate assumption, and it might be wrong, but that's just what I think it'd be.

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3 years ago
How many solutions does this equation have? 6x+5=4x+5
Travka [436]

:\implies \sf  6x +5 = 4x +5

: \implies \sf  6x +5 -4x = 5

:\implies \sf  2x = 5-5

:\implies \sf  2x = 0

:\implies \sf  x = 0

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2 years ago
A school has 1800 students and 1800 light bulbs, each with a pull cord and all in a row. All the lights start out off. The first
Gnom [1K]

<u>Solution-</u>

A school has 1800 students and 1800 light bulbs, each with a pull cord and all in a row.

As all the lights start out off, in the first pass all bulbs will be turned on.

In the second pass all the multiples of 2 will be off and rest will be turned on.

In the third pass all the multiples of 3 will be off, but the common multiple of 2 and 3 will be on along with the rest. i.e all the multiples of 6 will be turned on along with the rest.

In the fourth pass 4th light bulb will be turned on and so does all the multiples of 4.

But, in the sixth pass the 6th light bulb will be turned off as it was on after the third pass.

This pattern can observed that when a number has odd number of factors then only it can stay on till the last pass.

1 = 1

2 = 1, 2

3 = 1, 3

<u>4 = 1, 2, 4</u>

5 = 1, 5

6 = 1, 2, 3, 6

7 = 1, 7

8 = 1, 2, 4, 8

9 = 1, 3, 9

10 = 1, 2, 5, 10

11 = 1, 11

12 = 1, 2, 3, 4, 6, 12

13 = 1, 13

14 = 1, 2, 7, 14

15 = 1, 3, 5, 15

16 = 1, 2, 4, 8, 16

so on.....

The numbers who have odd number of factors are the perfect squares.

So calculating the number of perfect squares upto 1800 will give the number of light bulbs that will stay on.

As,  \sqrt{1800} =42.42  , so 42 perfect squared numbers are there which are less than 1800.

∴ 42 light bulbs will end up in the on position. And there position is given in the attached table.

7 0
3 years ago
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