Nancy has 62 more erasers than Barbara. Barbara has ferasers. Write the expression that

If m 2 n, which inequalities must be true? Check all that apply.

anzhelika [568]

Answer:

$(a)\ m+ 2.1 > n + 2.1$

$(b).\ m - (-4) > n - (-4)$

$(c)\ 9 +m> 6 + n$

Step-by-step explanation:

Given

$m > n$

Required

Select true inequalities

$(a)\ m+ 2.1 > n + 2.1$

Subtract 2.1 from both sides

$m > n$

This is true

$(b).\ m - (-4) > n - (-4)$

Open brackets

$m + 4 > n + 4$

Subtract 4 from both sides

$m > n$

$(c)\ 9 +m> 6 + n$

$m> -9+6 + n$

$m> n-3$

This is also true

8 0

3 years ago

Read 2 more answers

How many thumbs down votes did the video get

lara31 [8.8K]

So you have the ratio of 9:2.

The video has 18 thumbs up votes with the ratio being thumbs up to thumbs down.

9 in relation to 18 is times 2 so it makes since to times 2 by 2.

Therefore the ratio would be 18:4 which means there would be 4 thumbs down.

4 0

3 years ago

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

3 years ago

Is 8.54 rational i am stuck and cant find answers

mina [271]

Yes 8.54 as rational number because in can be written as 854/100

5 0

4 years ago

Read 2 more answers

6. Give examples of methods to safeguard inventory.

snow_lady [41]

Answer:

1. Security Technology. ...

2. Security Personnel. ...

3. Inventory Audits. ...

4. Just-in-Time Inventory.

Step-by-step explanation:

Reviewing a few examples of safeguarding inventory can shed light on common inventory security methodologies, helping you to implement the ideal inventory safeguards for your business.

Security Technology. ...

Security Personnel. ...

Inventory Audits. ...

Just-in-Time Inventory.

5 0

2 years ago