What is the constant of proportionality for the relationship shown in this table?
1 answer:
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Answer:
(a) 1.94
(b) 1.94
(c) 1.05
(d) 1.15
(e) 0.44
(f) 0.44
Step-by-step explanation:
A standard normal distribution has mean 0 and standard deviation 1.
(a)
The value of <em>z</em> for which P (Z < z) = 0.9738 is:
<em>z</em> = 1.94
(b)
Compute the value of <em>z</em> for which the area between 0 and <em>z</em> is 0.4738 as follows:
The value of <em>z</em> is,
<em>z</em> = 1.94
(c)
The value of <em>z</em> for which P (Z < z) = 0.8531 is:
<em>z</em> = 1.05
(d)
The value of <em>z</em> for which P (Z > z) = 0.1251 is:
<em>z</em> = 1.15
(e)
The value of <em>z</em> for which P (Z < z) = 0.67 is:
<em>z</em> = 0.44
(f)
The value of <em>z</em> for which P (Z > z) = 0.33 is:
<em>z</em> = 0.44
**Use the <em>z</em>-table.
