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bearhunter [10]
3 years ago
7

Triangle ABC is similar to triangle FGH. What is the value of x in centimeters?

Mathematics
1 answer:
garri49 [273]3 years ago
3 0

Answer:

pythagorean theorem

18

Step-by-step explanation:

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There is a bag filled with 4 blue and 5 red marbles.
Rom4ik [11]

Answer:

I think its 2/9 but im not sure worth a try doe

3 0
3 years ago
PLEASE HELP
riadik2000 [5.3K]

Answer:

Ok. so let's teach you how to find the angles of a triangle. When you add all three sides, they must equal 180 degrees. Because of this, let's do some math. What is 96+35. Ima pretend you said 131 and so you would be right. Now let's subtract that from 180 degrees. 180-131 is 49 and so x is 49 degrees. Hope this helps!!

3 0
2 years ago
Determine the gradient of the straight line 2x-3y+9=0. Find the equation of the straight line through the origin which is perpen
frutty [35]

Answer: 3

x

−

2

y

−

15

=

0

Explanation:

We know that,

the slope of the line  

a

x

+

b

y

+

c

=

0

is  

m

=

−

a

b

∴

The slope of the line  

2

x

+

3

y

=

9

is  

m

1

=

−

2

3

∴

The slope of the line perpendicular to  

2

x

+

3

y

=

9

is  

m

2

=

−

1

m

1

=

−

1

−

2

3

=

3

2

.

Hence,the equn.of line passing through  

(

3

,

−

3

)

and

m

2

=

3

2

is

y

−

(

−

3

)

=

3

2

(

x

−

3

)

y

+

3

=

3

2

(

x

−

3

)

⇒

2

y

+

6

=

3

x

−

9

⇒

3

x

−

2

y

−

15

=

0

Note:

The equn.of line passing through  

A

(

x

1

,

y

1

)

and

with slope

m

is

y

−

y

1

=

m

(

x

−

x

1

)3

x

−

2

y

−

15

=

0

Explanation:

We know that,

the slope of the line  

a

x

+

b

y

+

c

=

0

is  

m

=

−

a

b

∴

The slope of the line  

2

x

+

3

y

=

9

is  

m

1

=

−

2

3

∴

The slope of the line perpendicular to  

2

x

+

3

y

=

9

is  

m

2

=

−

1

m

1

=

−

1

−

2

3

=

3

2

.

Hence,the equn.of line passing through  

(

3

,

−

3

)

and

m

2

=

3

2

is

y

−

(

−

3

)

=

3

2

(

x

−

3

)

y

+

3

=

3

2

(

x

−

3

)

⇒

2

y

+

6

=

3

x

−

9

⇒

3

x

−

2

y

−

15

=

0

Note:

The equn.of line passing through  

A

(

x

1

,

y

1

)

and

with slope

m

is

y

−

y

1

=

m

(

x

−

Explanation:

the equation of a line in  

slope-intercept form

is.

∙

x

y

=

m

x

+

b

where m is the slope and b the y-intercept

rearrange  

2

x

+

3

y

=

9

into this form

⇒

3

y

=

−

2

x

+

9

⇒

y

=

−

2

3

x

+

3

←

in slope-intercept form

with slope m  

=

−

2

3

Given a line with slope then the slope of a line

perpendicular to it is

∙

x

m

perpendicular

=

−

1

m

⇒

m

perpendicular

=

−

1

−

2

3

=

3

2

⇒

y

=

3

2

x

+

b

←

is the partial equation

to find b substitute  

(

3

,

−

3

)

into the partial equation

−

3

=

9

2

+

b

⇒

b

=

−

6

2

−

9

2

=

−

15

2

⇒

y

=

3

2

x

−

15

2

←

equation of perpendicular lineExplanation:

the equation of a line in  

slope-intercept form

is.

∙

x

y

=

m

x

+

b

where m is the slope and b the y-intercept

rearrange  

2

x

+

3

y

=

9

into this form

⇒

3

y

=

−

2

x

+

9

⇒

y

=

−

2

3

x

+

3

←

in slope-intercept form

with slope m  

=

−

2

3

Given a line with slope then the slope of a line

perpendicular to it is

∙

x

m

perpendicular

=

−

1

m

⇒

m

perpendicular

=

−

1

−

2

3

=

3

2

⇒

y

=

3

2

x

+

b

←

is the partial equation

to find b substitute  

(

3

,

−

3

)

into the partial equation

−

3

=

9

2

+

b

⇒

b

=

−

6

2

−

9

2

=

−

15

2

⇒

y

=

3

2

x

−

15

2

←

equation of perpendicular line

7 0
3 years ago
Read 2 more answers
In the coordinate plane, the point A, 4− 2 is translated to the point A′, 1− 5. Under the same translation, the points B, 7− 4 a
Inga [223]

Answer:

The coordinates of B' and C' are B'(x,y) = (4, -7) and C'(x,y) = (-1, -8), respectively.

Step-by-step explanation:

From the Linear Algebra, we define the translation of a given point as:

O'(x,y) = O(x,y) + T(x,y) (1)

Where:

O(x,y) - Original point, dimensionless.

T(x,y) - Translation vector, dimensionless.

O'(x,y) - Translated point, dimensionless.

If we know that A'(x,y) = (1, -5) and A(x,y) = (4,-2), then the translation vector is:

T(x,y) = A'(x,y)-A(x,y) (2)

T(x,y) = (1,-5)-(4,-2)

T(x,y) = (-3,-3)

If we know that B(x,y) = (7,-4), C(x,y) = (2,-5) and T(x,y) = (-3,-3), then the translated points are, respectively:

B'(x,y) = B(x,y)+T(x,y) (3)

B'(x,y) = (7,-4) +(-3,-3)

B'(x,y) = (4, -7)

C'(x,y) = C(x,y) +T(x,y)

C'(x,y) = (2,-5) + (-3,-3)

C'(x,y) = (-1, -8)

The coordinates of B' and C' are B'(x,y) = (4, -7) and C'(x,y) = (-1, -8), respectively.

5 0
2 years ago
PLEASE HELP! ASAP! WILL MARK BRAINLIEST IF CORRECT!!!!!
Volgvan

Answer:

D.............................................

Step-by-step explanation:

im sorry if im wrong

6 0
2 years ago
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