Answer:
Explanation:
For this case we have to go through molecules to moles, from moles to grams and finally from grams to mg. The ratios that we have to take into account are:
-) <u>1 mol = 6.023x10^23 molecules</u>
-) The molar mass of <u>180.16 g = 1 mol</u>
-) <u>1 g= 1000 mg</u>
With this in mind we can do the calculation:
Answer:
The mass percent of a solution of 7.6 grams sucrose in 83.4 grams of water is 8.351 %.
Explanation:
Given,
Mass of Sucrose = 7.6 grams
Mass of Water = 83.4 grams
In this solution, Sucrose is solute and water is the solvent.
Mass percent of a solution can be calculated using the formula,
Mass percent = (Mass of Solute/Mass of Solution)(100)
As sucrose is solute, mass of solute = 7.6 grams
As the solution contains both Sucrose and Water,
Mass of solution = 7.6 grams + 83.4 grams = 91 grams
Substituting the values, Mass percent = (7.6/91)(100) = 8.351 %.
Answer:
Conc. of acetic acid in vinegar = 0.573M
%(mass) of acetic acid = 3.40%
Explanation:
All working is shown in pic.
A. an ionic bond dslslslslsks