Answer:
use the formula pressure 1 ÷ temperature 1 = pressure 2 ÷ temp 2
so your equation would look like this,
p2= p1(T2)÷ T1
so p2 =5.5(18)÷23
so it would be 4.304347826
round as you must
Answer:
B
Explanation:
because polarity of the water molecules is due to the B. deflection of the hydrogen atoms by the lone pair of electrons.
Answer:
Likely an issue with the mitral valve.
Explanation:
If I read this correctly, you are likely referring to mitral regurgitation, which is a process where your mitral value does not close tightly enough to stop the blood to flow into left atrium.
Normally, when the left ventricle is full, the mitral valve shuts to prevent blood blood from flowing backward into the atrium while the ventricle contracts, and this allows for blood to go to aorta and to body. According to question since the process is reversed, I am gonna go out on a limb and say mitral valve is likely the structure affected by this since and how I came to conclusion is all the explaintion I did earlier.
Answer:
1A, 3B, and 7A are examples of group _ on the periodic table. ... Elements in group 2 are all called alkaline earth metals.
Explanation:
![m(\text{CO}_2) = 2.24 \; \text{g}](https://tex.z-dn.net/?f=%20m%28%5Ctext%7BCO%7D_2%29%20%3D%202.24%20%5C%3B%20%5Ctext%7Bg%7D%20)
Ethene react with oxygen at a
molar ratio:
![2\; \text{C}_2 \text{H}_6 (g) + 7\; \text{O}_2 (g) \to 6\; \text{H}_2{O} (g) + 4\; \text{CO}_2 (g)](https://tex.z-dn.net/?f=%202%5C%3B%20%5Ctext%7BC%7D_2%20%5Ctext%7BH%7D_6%20%28g%29%20%2B%207%5C%3B%20%5Ctext%7BO%7D_2%20%28g%29%20%5Cto%206%5C%3B%20%5Ctext%7BH%7D_2%7BO%7D%20%28g%29%20%2B%204%5C%3B%20%5Ctext%7BCO%7D_2%20%28g%29%20%20)
Convert the quantity of each reactant supplied to number of moles of particles:
The question stated not whether both reactants were used up in this process. Thus start by testing the assumption that e.g., ethene was used up while some oxygen gas were left unreacted (ethene as the <em>limiting </em>reagent.) Under this assumption, the relative availability of the two species,
and
(as seen in the balanced chemical equation) shall satisfy the relationship
![n(\text{O}_2) / 7 - n(\text{C}_2 \text{H}_6) / 2 > 0](https://tex.z-dn.net/?f=%20%20n%28%5Ctext%7BO%7D_2%29%20%2F%207%20-%20n%28%5Ctext%7BC%7D_2%20%5Ctext%7BH%7D_6%29%20%2F%202%20%3E%200%20)
In other words,
![n(\text{O}_2)/7 > n(\text{C}_2 \text{H}_6)/2](https://tex.z-dn.net/?f=%20n%28%5Ctext%7BO%7D_2%29%2F7%20%3E%20n%28%5Ctext%7BC%7D_2%20%5Ctext%7BH%7D_6%29%2F2%20%20)
![n(\text{C}_2 \text{H}_6) / n(\text{O}_2) < 2/7 \approx 0.286](https://tex.z-dn.net/?f=%20%20n%28%5Ctext%7BC%7D_2%20%5Ctext%7BH%7D_6%29%20%2F%20n%28%5Ctext%7BO%7D_2%29%20%3C%202%2F7%20%5Capprox%200.286)
Evaluating the expression
with data given in the question yields approximately
, which does satisfy the relationship. Hence the assumption holds and ethene is the limiting reactant.
The quantity of a reactant produced in a chemical reaction is related to its stoichiometric (of relating to proportions) relationship with the limiting reactant (or any of the reactants in case of more than one limiting reactant.) For this scenario, given the molar ratio
,
![n(\text{CO}_2) = n(\text{C}_2\text{H}_6) \cdot (2 / 4) = 0.0510 \; \text{mol}](https://tex.z-dn.net/?f=%20n%28%5Ctext%7BCO%7D_2%29%20%3D%20n%28%5Ctext%7BC%7D_2%5Ctext%7BH%7D_6%29%20%5Ccdot%20%282%20%2F%204%29%20%3D%200.0510%20%5C%3B%20%5Ctext%7Bmol%7D%20)
![m(\text{CO}_2) = 0.0510 \; \text{mol} \times 44.01 \; \text{g} \cdot \text{mol}^{-1} = 2.24 \; \text{g}](https://tex.z-dn.net/?f=%20m%28%5Ctext%7BCO%7D_2%29%20%3D%200.0510%20%5C%3B%20%5Ctext%7Bmol%7D%20%5Ctimes%2044.01%20%5C%3B%20%5Ctext%7Bg%7D%20%5Ccdot%20%20%5Ctext%7Bmol%7D%5E%7B-1%7D%20%3D%202.24%20%5C%3B%20%5Ctext%7Bg%7D%20)