1. to calculate molar mass , you need average atomic mass of each element.
formula is simple
suppose we have Na2CO3
here it says
there are
2 atoms of Na
1 atom of C
3 atom of O
now
molar mass = (total atoms of Na × average atomic mass of Na) + ( total atom of C × average atomic mass of C )+ (total atom of O × average atomic mass of O)
i hope you can figure out it now.
in case of (NH4)2
this means you have 2 count of NH4
so total atoms of N = 2
total atoms of H = 4×2 = 8
so on you can now figure it out
2. balanced equation
here LHS and RHS shoild have same number of atoms of each element .
for example
H2 + Cl2 => 2HCl
here 2 atoms of H combined with 2 atoms of Cl , we know H and Cl combined and formed HCl now because total H atoms are 2 and Cl atoms are 2 in LHS then we should also have 2 atoms of each in right side
so thats why we have 2HCl in right side.
Try to figure out . let me know if need any help
Answer: precipitate.
Explanation:
1) When the product of the reaction between the chemicals in the solution is insoluble, then it cannot remain in the solution and it will precipiate, forming a solid substance.
2) That happens, for example, when you have two solutions with different solutes, mix them together, the solutes can react chemically with each other, yielding a product that is insoluble.
3) A typical example of such kind of precipitation reactions is athe neutralization of an acid and a base.
Acid + Base = salt + water
If the salt is insoluble in water then it will form a a precipitate (solid), if the product is soluble in water then it remains as an aqueos ions in the solution.
Answer:
Between 4s and 3s orbital , 3s has more energy .
Explanation:
According to the rule , the lower the value of (n+l) for an orbital , the lower is it's energy . And if two orbitals have the same value of (n+l), the orbital with lower value of n will have the lower energy .
Answer:
The answer to your question is below
Explanation:
a) HCl 0.01 M
pH = -log [0.01]
pH = - (-2)
pH = 2
b) HCl = 0.001 M
pH = -log[0.001]
pH = -(-3)
pH = 3
c) HCl = 0.00001 M
pH = -log[0.00001]
pH = - (-5)
pH = 5
d) Distilled water
pH = 7.0
e) NaOH = 0.00001 M
pOH = -log [0.00001]
pOH = -(-5)
pH = 14 - 5
pH = 9
f) NaOH = 0.001 M
pOH =- log [0.001]
pOH = 3
pH = 14 - 3
pH = 11
g) NaOH = 0.1 M
pOH = -log[0.1]
pOH = 1
pH = 14 - 1
pH = 13
