Incomplete question. However, let's assume this are feasible regions to consider:
Points:
- (0, 100)
- (0, 125)
- (0, 325)
- (1, 200)
Answer:
<u>Maximum value occurs at 325 at the point (0, 325)</u>
<u>Step-by-step explanation:</u>
Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.
- For point (0, 100): P= 2(0) + 1.5 (100) =150
- For point (0, 125): P= 2(0) + 1.5 (125) =187.5
For point (0, 325): P= 2(0) + 1.5 (325) = 487.5
For point (1, 200): P= 2(1) + 1.5 (200) = 302
Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.
Answer:
Rob saved $24 on Saturday.
Step-by-step explanation:
Given:
Rob is saving to buy a new MP3 player.
Money earned in baby sitting = $11
Money saved =$6
First we will find the Percentage of amount he saved.
Percentage of amount he saved can calculated by Amount saved divided by total money earned and then multiplying by 100.
framing in equation form we get;
Percentage of amount he saved = 
Now Given:
Money earned in babysitting on Saturday = $44
We need to find the Money he saved on Saturday.
Money Saved can be calculated by Percentage of amount he saved multiplying by Money earned in babysitting on Saturday and then divided by 100.
framing in equation form we get;
Money Saved on Saturday = 
Hence Rob saved $24 on Saturday.
<em><u>Question:</u></em>
Hector has a floor plan showing his new house. On the floor plan, his bedroom is 3 inches wide and 3 1/2 inches long. The scale of the floor plan is 1/4 inch = 1 foot. What is the actual length of Hector’s room?
<em><u>Answer:</u></em>
The actual length of Hector room is 14 foot
<em><u>Solution:</u></em>
Given that, On the floor plan, his bedroom is 3 inches wide and
inches long
<em><u>The scale of floor plan is given as:</u></em>

Therefore,

To find: Actual length of floor
From given question,

Converting the mixed fraction to improper fraction,

Since, 1 inch = 4 foot

Thus actual length of Hector room is 14 foot
Answer:
l=0.1401P\\
w =0.2801P
where P = perimeter
Step-by-step explanation:
Given that a window is in the form of a rectangle surmounted by a semicircle.
Perimeter of window =2l+\pid/2+w

Or 
To allow maximum light we must have maximum area
Area = area of rectangle + area of semi circle where rectangle width = diameter of semi circle


Hence we get maximum area when i derivative is 0
i.e. 

Dimensions can be

She would have to score atleast a 74 on the test for her average to be 78