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2 years ago

G(x) = -3х (х^2– 36) (х – 6) Find all real zeros of the function

Mathematics

1 answer:

Daniel [21]2 years ago

6 0

Aren’t there only 2? Because of the squared exponent? I’m not fully sure

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Help with number 12 please

Troyanec [42]

The fifth power of ten would not be represented.
Each individual digit would be shown as a power of ten.
982 would be the sum of:
9 times 100. (100 is 10 to the second power)
plus
8 times 10. (10 is 10 to the first power.)
plus
2 times 1. (I is 10 to the zero power.)

The only significant digit represented by a zero is the "hundred thousands"
(100,000 is 10 to the fifth power.)

4 0

2 years ago

Can anyone help me with #3 on this please

spayn [35]

Answer:

So I can't actually do this at the moment but I'll try to explain what to do

first find the area of the rectangle (12x16)

then, the confusing part, pretend the semicircle is a full circle and find the area and divide by 2

add the two up and put $cm^{2}$ and that should be it

7 0

3 years ago

What is the equation, in slope-intercept form, of the line that is perpendicular to the line

NeTakaya

Answer:

y = -x - 4

Step-by-step explanation:

First find the slope

y - 4 = (x - 6)

y - 4 = x - 6

y = x - 6 + 4

y = x - 2 (y = mx + C)

Slope m = 1

It is said that the line is perpendicular to a point ( -2, -2)

If two lines are perpendicular, their slope will be negative reciprocal

The negative reciprocal of slope = 1 is -1

Using a slope intercept form as requested by the question

y = mx + C

Inserting the values given

(-2, -2)

We are using point slope form

y - y_1 = m ( x - x_1)

x_1 = -2

y_1 = -2

m = -1

Insert the values

y - ( -2)) = -1( x - (-2))

y + 2 = -1 ( x + 2)---- point slope form

But we are requested to give the answer in slope intercept form

y = mx + C

We have to open the bracket

y + 2 = -1(x + 2)

y + 2 = -x - 2

y = -x - 2 - 2

y = -x - 4 ( slope - intercept form)

4 0

3 years ago

Write two expressions where the solution is 28

konstantin123 [22]

10+18=28
17+11=28

OR

2x=28 where x=14
4x where x=7

8 0

2 years ago

If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how

Goryan [66]

Rates are used to measure a quantity over another.

The 1.8 million cars use $1.85 \times 10^{10}$ liters each year

Given

$Cars = 1.8\ million$

$d = 17500km$ --- distance

$r = 40miles/gallon$

First, we calculate the number (n) of gallons used by each car

$r = \frac{d}{n}$

Solve for n

$n = \frac{d}{r}$

So, we have:

$n = \frac{17500km}{40miles/gallon}$

$n = \frac{17500km}{40miles}gallon$

Convert miles to kilometers

$n = \frac{17500km}{40km \times 1.60934}gallon$

$n = \frac{17500km}{64.3738km}gallon$

$n = 271.85\ gallon$

The number of gallons (N), used by all the cars is:

$N = n \times cars$

$N = 271.85 \times 1.8\ million$

$N = 489330000$

Convert to liters

$N = 489330000 \times 3.78541L$

$N = 1852314675.3L$

In scientific notation to 2 decimal places, we have:

$N = 1.85 \times 10^{10}L$

Hence, the number of liters used is $1.85 \times 10^{10}$

Read more about distance and rates at:

brainly.com/question/24659604

4 0

2 years ago