Answer:
<h3>X<5 and X<3</h3>
Step-by-step explanation:
To solve this problem, first, you have to isolate it on one side of the equation. Remember to solve this problem, isolate x on one side of the equation.
x+3<8 and 3(x+4)-11<10
x+3<8
x+3-3<8-3 (First, subtract 3 from both sides.)
8-3 (Solve.)
8-3=5
x<5
3(x+4)-11<10
3(x+4)-11+11<10+11 (Add 11 from both sides.)
10+11 (Solve.)
10+11=21
3(x+4)<21
3(x+4)/3<21/3 (Next, divide by 3 from both sides.)
21/3 (Solve.)
21/3=7
x+4<7
x+4-4<7-4 (Then, subtract 4 from both sides.)
7-4=3
x<3
The correct answer is x<5 and x<3.
3√x+2 = √x+4
divide both sides by 3
√x+2 = √x+4 / 3
remove radical by squaring both sides
x+2 = x+4/9
x+2 = x/9 + 4/9 =
8x/9 = -14/9
8x*9 = -14*9=
72x = -126
x = -7/4
