Answer:
One is 3x+2 while the other is 2x-1
Step-by-step explanation:
It is opposite to one another
the one with 3x+2 is opposite to the non given one and the one withb2x-1 is opposite
Hello!
We don't need to find the exact perimeter of the fencing, just an estimate.
We will round 12 ft 3 in to 12 ft, because it is closer to 12 ft than 13 ft.
We will also round 8 ft 11 in to 9 ft because there are 12 inches in a foot, which makes 9 ft closer.
The formula for perimeter of a rectangle is:
P = 2l × 2w
The length is about 12 feet and the width is about 9 feet.
Substitute the length and width:
P = 2(12) + 2(9)
Solve:
P = 24 + 18
P = 42
Jose will need about 42 feet of fencing.
A) For the equation

, the slope is

.
Slope-intercept form is y = mx + b, where m is slope and b is the y-intercept. This means that if

, the slope is

.
B) Since this equation is in the same form, you just find what m is equal to.
Since

, that's the slope.
For the solution, set

equal to

, so it would be put together like this:
![y=[tex]- \frac{1}{2}x+3=2x-4\\ -\frac{1}{2}=2x-7\\ 1\frac{1}{2}x=-7\\ x=-4.66667](https://tex.z-dn.net/?f=y%3D%5Btex%5D-%20%5Cfrac%7B1%7D%7B2%7Dx%2B3%3D2x-4%5C%5C%20-%5Cfrac%7B1%7D%7B2%7D%3D2x-7%5C%5C%201%5Cfrac%7B1%7D%7B2%7Dx%3D-7%5C%5C%20x%3D-4.66667)
So your answer is
-4.667.
Answer:
D
Step-by-step explanation:
Neither table os a linear relation
Answer:
the two roots are x = 1 and x = 4
Step-by-step explanation:
Data provided in the question:
(x³ − 64) (x⁵ − 1) = 0.
Now,
for the above relation to be true the following condition must be followed:
Either (x³ − 64) = 0 ............(1)
or
(x⁵ − 1) = 0 ..........(2)
Therefore,
considering the first equation, we have
(x³ − 64) = 0
adding 64 both sides, we get
x³ − 64 + 64 = 0 + 64
or
x³ = 64
taking the cube root both the sides, we have
∛x³ = ∛64
or
x = ∛(4 × 4 × 4)
or
x = 4
similarly considering the equation (2) , we have
(x⁵ − 1) = 0
adding the number 1 both the sides, we get
x⁵ − 1 + 1 = 0 + 1
or
x⁵ = 1
taking the fifth root both the sides, we get
![\sqrt[5]{x^5}=\sqrt[5]{1}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E5%7D%3D%5Csqrt%5B5%5D%7B1%7D)
also,
1 can be written as 1⁵
therefore,
![\sqrt[5]{x^5}=\sqrt[5]{1^5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E5%7D%3D%5Csqrt%5B5%5D%7B1%5E5%7D)
or
x = 1
Hence,
the two roots are x = 1 and x = 4