Answer:
Average atomic mass = 15.86 amu.
Explanation:
Given data:
Number of atoms of Z-16.000 amu = 205
Number of atoms of Z-14.000 amu = 15
Average atomic mass = ?
Solution:
Total number of atoms = 205 + 15 = 220
Percentage of Z-16.000 = 205/220 ×100 = 93.18%
Percentage of Z-14.000 = 15/220 ×100 = 6.82 %
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (93.18×16.000)+(6.82×14.000) /100
Average atomic mass = 1490.88 + 95.48 / 100
Average atomic mass = 1586.36 / 100
Average atomic mass = 15.86 amu.
Answer:
nitrogen monoxide: NO
nitrogen dioxide: NO₂
Explanation:
Nitrogen monoxide is composed by 1 atom of O (prefix "mono-") and 1 atom of N. Nitrogen dioxide is composed by 2 atoms of O (prefix "di-") and 1 atom of N. As the oxigen atom in oxides has the valency -2 (it shares 2 electrons), the nitrogen has valency +2 in NO and +4 in NO₂.
Atoms are electrically neutral because they have equal numbers of protons positively charged and electrons negatively charged.if an atom gains or loses one or more electrons it becomes an ion
Answer:
[H⁺] = 1.58x10⁻⁶M; [OH⁻] = 6.31x10⁻⁹M.
pH = 8.23; pOH = 5.77
Explanation:
pH is defined as <em>-log [H⁺]</em> and also you have <em>14 = pH + pOH </em>
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Thus, for a solution of pH = 5.80.
5.80 = -log [H⁺] → [H⁺] = 10^-(5.80) = 1.58x10⁻⁶M
pOH = 14-5.80 = 8.20 → [OH⁻] = 10^-(8.20) = 6.31x10⁻⁹M
Thus, for a solution of [H⁺] = 5.90x10⁻⁹M and pH = -log 5.90x10⁻⁹M = 8.23
And pOH = 14-8.23 = 5.77
