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prohojiy [21]
3 years ago
8

The larger the molecules of a substance, the the London forces between them. A larger molecule has more electrons and a greater

of having its electron cloud distorted from its nonpolar shape. Thus instantaneous dipoles are more likely to form in larger molecules. The electron clouds in larger molecules are also larger, so the average distance between the nuclei and the electrons is greater; as a result, the electrons are held and shift more easily to create a dipole.
True / False.
Chemistry
1 answer:
aev [14]3 years ago
6 0

Answer:

True

Explanation:

All the above statements buttress the fact that the larger molecule, the greater the magnitude of London forces between the molecules. Each of the statements above is a confirmation/explanation of this general rule.

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PLEASE HELP!!
NARA [144]
We can skip option B and D because NaCl is salt and H₂SO₄ is a strong acid.
Neutralization reactions are those reactions in which acid and base react to form salt and water.
As water being amphoteric in nature can react with HCl as follow,

                           HCl  +  H₂O   ⇆  H₃O⁺  +  OH⁻

In this case no salt is formed, so we can skip this option.

Ammonia being a weak base can abstract proton from HCl as follow,

                              HCl  +  NH₃  →  NH₄Cl

Ammonium Chloride is a salt. So, among all four options, Option-C is the correct answer.
3 0
3 years ago
Read 2 more answers
Please help, thanks!
Anastasy [175]
You need to use the formula--> P1V1= P2V2 (Boyles's law)

P1= 14 bar
V1= 312 mL
P2= ?
V2= 652 mL

now we plug the values into the formula.

(14 x 312) = (P2x 652)

P2= (14 x 312)/ 652= <span>6.70 bar</span>
5 0
3 years ago
How many atoms are in one body-centered cubic unit cell of a metal?
Mashcka [7]

Answer:

Option B - 2

Explanation:

In Crystal lattices, there are different types of unit cells namely;

- Hexagonal Closest Packed (HCP)

- Face Centred Cubic (FCC)

- Body Centred Cubic (BCC)

- Simple Centred Cubic (SC)

Now, each of them have a coordination number and also number of atoms per unit cell.

For this question, we are restricted to the body-centered cubic (bcc) unit cell which has a coordination number of 8 and contains 2 atoms per unit cell.

3 0
4 years ago
What is the percent by mass of nahco3 in a solution containing 10 g of nahco3 dissolved in 400 ml of h2o?
Marat540 [252]
Answer is: the percent by mass of NaHCO₃ is 2,43%.
m(NaHCO₃) = 10 g.
V(H₂O) = 400 ml.
d(H₂O) = 1 g/ml.
m(H₂O) = V(H₂O) · d(H₂O).
m(H₂O) = 400 ml · 1 g/ml.
m(H₂O) = 400 g.
m(solution) = m(H₂O) + m(NaHCO₃).
m(solution) = 400 g + 10 g.
m(solution) = 410 g.
ω(NaHCO₃) = 10 g ÷ 410 g · 100%.
ω(NaHCO₃) = 2,43 %
7 0
3 years ago
You mix 125 mL of 0.170 M with 50.0 mL of 0.425 M in a coffee-cup calorimeter, and the temperature of both solutions rises from
kondaur [170]

Here is the correct question

You mix 125 mL of 0.170 M CsOH with 50.0 mL of 0.425 M HF in a coffee-cup calorimeter, and the temperature of both solutions rises from 20.20 °C before mixing to 22.17 °C after the reaction. What is the enthalpy of reaction per mole of ? Assume the densities of the solutions are all 1.00 g/mL, and the specific heat capacities of the solutions are 4.2 J/g · K. Enthalpy of reaction = kJ/mol

Answer:

75.059 kJ/mol

Explanation:

The formula for calculating density  is:

density = \frac{mass}{volume}\\

Making mass the subject of the formula; we have :

mass = density × volume

which can be rewritten as:

mass of the solution =  density × volume of the solution

= 1.00 g/mL × (125+ 50 ) mL

= 175 g

Specific heat capacity = 4.2 J/g.K

∴ the energy absorbed is = mcΔT

= 175 × 4.2 × (22.17 - 20.00) ° C

= 1594.95 J

= 1.595 J

number of moles of CsOH =  \frac{125}{1000} *100

= 0.2125 mole

Therefore; the enthalpy of the reaction = \frac{Energy \ absorbed }{number \ of \ moles}

= \frac{1.595}{0.02125}

= 75.059 kJ/mol

5 0
3 years ago
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