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nirvana33 [79]
2 years ago
6

A 0.0200 m nacl solution was formed when 38.0 grams of nacl was dissolved in enough water. what was the total volume of the solu

tion formed? 32.5 liters 30.3 liters 26.7 liters 22.1 liters
Chemistry
1 answer:
Lostsunrise [7]2 years ago
3 0

Total volume of the solution formed will be 32.5 liters

Given:

Molarity of solution = 0.0200 m

mass of nacl = 38.0 grams

To Find:

total volume of the solution

Solution: Molarity is defined as the amount of solute present in 1 L of solution. The equation used to determine molarity of the solution follows:

M = given mass of nacl/molar mass of nacl*1/volume of solution

volume of solution = given mass/molar mass*1/molarity

volume = 38/58.5*1/0.02 = 32.5

Hence, volume of solution = 32.5 litres

Learn more about Molarity here:

brainly.com/question/26873446

#SPJ4

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What is the concentration (in M) of a sample of the unknown dye with an absorbance of 0.25 at 542 nm?
Sladkaya [172]

Answer:

see explanation below

Explanation:

Question is incomplete, so in picture 1, you have a sample of this question with the missing data.

Now, in general terms, the absorbance of a substance can be calculated using the beer's law which is the following:

A = εlc

Where:

ε: molar absortivity

l: distance of the light in solution

c: concentration of solution

However, in this case, we have a plot line and a equation for this plot, so all we have to do is replace the given data into the equation and solve for x, which is the concentration.

the equation according to the plot is:

A = 15200c - 0.018

So solving for C for an absorbance of 0.25 is:

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If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol
igomit [66]

Answer:

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Explanation:

Hello,

In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:

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Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:

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Best regards.

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