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nirvana33 [79]
1 year ago
6

A 0.0200 m nacl solution was formed when 38.0 grams of nacl was dissolved in enough water. what was the total volume of the solu

tion formed? 32.5 liters 30.3 liters 26.7 liters 22.1 liters
Chemistry
1 answer:
Lostsunrise [7]1 year ago
3 0

Total volume of the solution formed will be 32.5 liters

Given:

Molarity of solution = 0.0200 m

mass of nacl = 38.0 grams

To Find:

total volume of the solution

Solution: Molarity is defined as the amount of solute present in 1 L of solution. The equation used to determine molarity of the solution follows:

M = given mass of nacl/molar mass of nacl*1/volume of solution

volume of solution = given mass/molar mass*1/molarity

volume = 38/58.5*1/0.02 = 32.5

Hence, volume of solution = 32.5 litres

Learn more about Molarity here:

brainly.com/question/26873446

#SPJ4

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Answer:

denotes the molar hydrogen ion concentration

Explanation:

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In a previous problem, the empirical formula of a compound of phosphorus and oxygen was found to be p2o5. experimentation shows
agasfer [191]
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we have to first find the number of empirical units in the molecular formula 
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3 0
3 years ago
“Dry ice” is the solid form of carbon dioxide. Determine the number of mass of CO2 gas in grams that are present in 61.8 L of CO
Fofino [41]

Answer:

Mass  = 121 g

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Given data:

Mass in gram of CO₂ = ?

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PV = nRT

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T = temperature in kelvin

1 atm × 61.8 L = n ×0.0821 atm.L/ mol.K   × 273.15 k

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6 0
2 years ago
What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP?
BigorU [14]
Mg reaction with O₂ gas will produce MgO so the equation will be
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The first step is to find the number of moles of Mg in 4.03g of Mg.  You can do this by dividing 4.03g Mg by its molar mass (which is 24.3g/mol) to get 0.1658mol Mg.  Then you have to find the number of moles of O₂ that will react with 0.1658mol Mg.  To do this you need to use the fact that 1mol O₂ will react with 2mol Mg (this reatio is from the chemical equation) so you have to multiply 0.1658mol Mg by (1mol O₂)/(2mol Mg) to get 0.0829mol O₂.  From here you would usually use PV=nRT and solve for V However, the question tells us that we are at STP, that means you can use the fact that 22.4L of gas is 1 mol of gas at STP.  Using that information we can find the volume of O₂ gas by mulitlying 0.0829mol O₂ by 22.4L/mol to get 1.857L which equals 1857mL.
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6 0
3 years ago
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An ionic bond forms when atoms blank electrons
8_murik_8 [283]

Answer:

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Explanation:

Ionic bonds are formed when atoms transfer electrons. (In contrast, covalent bonds are formed when atoms share electrons.)

There's a distinction between the two: when two atoms react to form an ionic bond, one atom would completely lose one electron, while the other would completely gain that electron. The atom that loses the electron becomes a positively-charged ion called a cation, whereas the atom that gains the electron becomes a negatively-charged ion called an anion.

For example, consider the reaction between a sodium \rm Na atom and a chlorine \rm Cl atom: \rm Na + Cl \to NaCl.

When the sodium atom and the chlorine atom encounter, the sodium atom would lose one electron to form a positively-charged sodium ion, \rm Na^{+}. The chlorine atom would gain that electron to form a negatively-charged chlorine ion \rm Cl^{-}.

These two ions will readily attract each other because of the opposite electrostatic charges on them. This electrostatic attraction (between two ions of opposite charges) is an ionic bond.

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In contrast, when two atoms react to form a covalent bond, they share electrons without giving any away completely. Therefore, it is possible to break certain covalent bonds apart (using a beam of laser, for example) and obtain neutral atoms.

On the other hand, when an ionic bond was broken, the result would be two charged ions- not necessarily two neutral atoms. The electron transfer could not be reversed by simply breaking the bond.

For example, when table salt \rm NaCl is melted (at a very high temperature,) the ionic bond between the sodium ions and chloride ions would (mostly) be broken. However, doing so would only generate a mixture of \rm Na^{+} and \rm Cl^{-} ions- not sodium and chlorine atoms.

7 0
2 years ago
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