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Vera_Pavlovna [14]
3 years ago
15

Easy 8th grade physics need some help don't answer if it isn't an answer :)

Physics
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

1b 2c 4f 5 a 6y

Explanation: i did this earlier

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A 1,200 kg subcompact car accelerates at a rate of 3.0m/s
ludmilkaskok [199]
Missing question (found on internet): 
"what is the force of the car?"

Solution:
According to Newton's second law, the force of the car is equal to the product between its mass and its acceleration:
F=ma
For the car in the problem,
m=1200 kg
a=3.0 m/s^2
So the force that accelerates the car is
F=(1200 kg)(3.0 m/s^2)=3600 N
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3 years ago
A ball dropped by melissa is falling downward toward the floor
Artist 52 [7]
What is the question
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3 years ago
A hockey puck is sliding across a frozen pond with an initial speed of 9.5 m/s. It comes to rest after sliding a distance of 37.
Bond [772]

Answer:

<h3>The coefficient of kinetic friction between the puck and the ice is \mu _{k} = 0.12</h3>

Explanation:

Given :

Initial speed  v_{o} = 9.5 \frac{m}{s}

Displacement x = 37.4 m

From the kinematics equation,

  v^{2} - v^{2} _{o}  = 2ax

Where v^{2}   = final velocity, in our example it is zero (v =0), a = acceleration.

   a =- \frac{90.25}{ 2 \times 37.4}

   a =- 1.21 \frac{m}{s^{2} }

From the formula of friction,

  F =- \mu _{k } N

Minus sign represent friction is oppose the motion

Where N = mg ( normal reaction force )

 ma = -\mu _{k}  m g                                                  ( ∵ g = 9.8 \frac{m}{s^{2} } )

So coefficient of friction,

 \mu_{k} = \frac{1.21}{9.8}

 \mu_{k} = 0.12

Therefore, the coefficient of kinetic friction between the puck and the ice is  \mu _{k} = 0.12 .

4 0
3 years ago
A bike race against the clock takes place on a straight road. Yan drives at 37 km / h and he starts the course 30s before Christ
joja [24]

Given data:

Yan speed;

u_1=37\text{ km/h}

Christopher speed;

u_2=38.9\text{ km/h}

Christophe starts 30 s later than Yan. Therefore, Christophe takes 30 s less than Yan to reach the same distance.

Part (A)

The distance is given as,

d=ut

Let both Yan and Christophe meet at d distance from the start position. Therefore,

u_1t=u_2(t-30)

Substituting all known values,

\begin{gathered} (37\text{ km/h})t=(38.9\text{ km/h})\times(t-30) \\ \frac{(37\text{ km/h})}{(38.9\text{ km/h})}=\frac{(t-30)}{t} \\ 0.95=1-\frac{30}{t} \\ \frac{30}{t}=1-0.95 \\ \frac{30}{t}=0.05 \\ t=\frac{30}{0.05} \\ t=600\text{ s} \end{gathered}

Therefore, 600 s after Yan's departure Christophe will join him.

Part (B)

The distance is given as,

d=u_1t

Substituting all known values,

\begin{gathered} d=(37\text{ km/h})\times(600\text{ s}) \\ =(37\text{ km/h})\times(600\text{ s})\times(\frac{1\text{ hr}}{3600\text{ s}}) \\ \approx6.17\text{ km} \end{gathered}

Therefore, Christophe joins Yan after 6.17 km from the start.

3 0
1 year ago
Explain what cause air pressure in your own words. Why do aircraft need pressurized cabins?
Jobisdone [24]
Because the atsmosphere in the sky makes it less gravity so air craft needs these cabins
7 0
3 years ago
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