Answer:
<u>Amplitude - remains the same</u>
<u>Frequency - increases</u>
<u>Period - decreases</u>
<u>Velocity - remains the same.</u>
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Explanation:
The amplitude of the wave remains the same since you are not changing the distance your hand moves and the amplitude of the wave depends on how much distance your hand covers while moving.
The frequency of your wave increases since now you are moving your hand more number of times in the same period i.e. your hand is moving faster in one second. So, the frequency of your wave increases.
The period is the time taken by the wave to travel a certain distance. Since your hand is now moving faster, the wave will travel faster and will take less time to cover the same distance hence, we can say that its period will decrease.
The velocity of a wave depends on the medium in which it is travelling. Your wave was previously travelling in air and the new wave is also travelling in the same medium so the velocity of the wave remains unchanged.
Since the electric field between the plates is constant
so we can say the relation between potential difference and electric field is given by
here from above relation we can say that is electric field is kept constant then potential difference is directly proportional to the distance between the plates
so here we will say that if the distance between the plates is decreased then the potential difference between the plates will also decreases
So correct answer will be
<u>a) decrease </u>
The force machines exert on objects are output forces.
Answer:
d = 771.3m
Explanation:
Let's first calculate the time of flight:
where Voy=0. Solving for t:
Now we calculate the horizontal displacement, wihch is the distance from the target to drop the package:
Xf = d = Vox*t
d = 180*4.285 = 771.3m