A 9.0 m long uniform rod with a weight of 8 N has 3 masses hanging from it; a 4N mass 1 meter from the left end, a 2 N mass 6 me
1 answer:
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Answer:
(a) surface area of the plate will be equal to
(b) Charge on the capacitor is equal to
Explanation:
We have given spacing between the plates d = 0.05 mm =
Value of capacitance
(A) Capacitance of a parallel plate capacitor is equal to
So
So surface area of the plate will be equal to
(B) It is given that capacitor is charged by 1.5 volt
So voltage V = 1.5 volt
Charge on the capacitor is equal to
So
The magnitude of the electrical force between a pair of charged particles is 4 Times as much when the particles are moved half as far apart.
This can be easily understood by Columb's law,
which state's that the amount of electrical force experienced by two charged particles is inversely proportional to the square of the distance between them.
∴
Now, we know the new distance is half the original distance,
The electrical force of attraction or electrostatic force of attraction between two charged particles refers to the amount of attractive or repulsive force that exists between the two charges. This can be calculated by Columb's Law.
A charged particle in physics is a particle that has an electric charge. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. The same charge is thought to be shared by an electron, a proton, or another primary particle.
Learn more about electrical force here
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