Answer:
Explanation:
The velocity at the inlet and exit of the control volume are same 
Calculate the inlet and exit velocity of water jet
The conservation of mass equation of steady flow
since inlet and exit velocity of water jet are equal so the inlet and exit cross section area of the jet is equal
The expression for thickness of the jet
R is the radius
t is the thickness of the jet
D_j is the diameter of the inlet jet
(b)
![R-x=\rho(AV_r)[-(V_i)+(V_c)\cos 60^o]\\\\=\rho(V_j+V_c)A[-(V_i+V_c)+(V_i+V_c)\cos 60^o]\\\\=\rho(V_j+V_c)(\frac{\pi}{4}D_j^2 )[V_i+V_c](\cos60^o-1)]](https://tex.z-dn.net/?f=R-x%3D%5Crho%28AV_r%29%5B-%28V_i%29%2B%28V_c%29%5Ccos%2060%5Eo%5D%5C%5C%5C%5C%3D%5Crho%28V_j%2BV_c%29A%5B-%28V_i%2BV_c%29%2B%28V_i%2BV_c%29%5Ccos%2060%5Eo%5D%5C%5C%5C%5C%3D%5Crho%28V_j%2BV_c%29%28%5Cfrac%7B%5Cpi%7D%7B4%7DD_j%5E2%20%29%5BV_i%2BV_c%5D%28%5Ccos60%5Eo-1%29%5D)
![R_x=[1000\times(44)\frac{\pi}{4} (10\times10^{-3})^2[(44)(\cos60^o-1)]]\\\\=-7603N](https://tex.z-dn.net/?f=R_x%3D%5B1000%5Ctimes%2844%29%5Cfrac%7B%5Cpi%7D%7B4%7D%20%2810%5Ctimes10%5E%7B-3%7D%29%5E2%5B%2844%29%28%5Ccos60%5Eo-1%29%5D%5D%5C%5C%5C%5C%3D-7603N)
The negative sign indicate that the direction of the force will be in opposite direction of our assumption
Therefore, the horizontal force is -7603N
Answer:
Create
Broken
Explanation:
Bond formation or creation requires the use of energy. Energy is used during bond formation between chemical species. The energy is required for the reaction to occur.
- When bonds are broken, energy is released
- Bond breaking process is a procedure that releases energy.
- This energy makes them able to react.
Given
Car 1
m1 = 1300 kg
v1 = 20 m/s
m2 = 900 kg
v2 = -15 m/s
(Negative sign shows that direction of car 2 is opposite to car 1)
Procedure
As per the conservation of linear momentum, "The total momentum of the system before the collision must be equal to the total momentum after the collision". And this applies to the perfectly inelastic collision as well. Then the expression is,
Thus, we can conclude that the speed and direction of the cars after the impact is 5.68 m/s towards the first car.
Answer:
a) Therefore 2.6km is greater than 2.57km.
Statement A is greater than statement B.
b) Therefore 5.7km is equal to 5.7km
Statement A is equal to statement B
Explanation:
a) Statement A : 2.567km to two significant figures.
2.567km 2. S.F = 2.6km
Statement B : 2.567km to three significant figures.
2.567km 3 S.F = 2.57km
Therefore 2.6km is greater than 2.57km.
Statement A is greater than statement B.
b) statement A: (2.567 km + 3.146km) to 2 S.F
(2.567km + 3.146km) = 5.713km to 2 S.F = 5.7km
Statement B : (2.567 km, to two significant figures) + (3.146 km, to two significant figures).
2.567km to 2 S.F = 2.6km
3.146km to 2 S.F = 3.1km
2.6km + 3.1km = 5.7km
Therefore 5.7km is equal to 5.7km
Statement A is equal to statement B
