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Sophie [7]
2 years ago
8

A 9.0 m long uniform rod with a weight of 8 N has 3 masses hanging from it; a 4N mass 1 meter from the left end, a 2 N mass 6 me

ters from the left end and a 3 N mass 4 meters from the left end. What force must be applied to bring the rod into total mechanical equilibrium
Physics
1 answer:
sweet-ann [11.9K]2 years ago
7 0

Answer:

Explanation:

Assume the rod is horizontal

Sum vertical forces to zero

F - 8 - 4 - 2 - 3 = 0

F = 17 N

While this result answers precisely the question asked, it is not sufficient to guarantee equilibrium. We must also locate this force by summing moments to zero. Let's choose to sum about the left end.

8[9/2] + 4[1] + 2[6] + 3[4] - 17[x] = 0

x = 3.76470588...

the force must be supplied upward approximately 3.765 m from the left end

The rod does not actually have to be horizontal. Moment arms will all be proportionately reduced by tilting the bar from horizontal and the results will be identical. Assuming horizontal just reduces the calculation effort.

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What could be the possible answer to the question ?<br><br>thankyou ~​
Ganezh [65]

The value of the force, F₀, at equilibrium is equal to the horizontal

component of the tension in string 2.

Response:

  • The value of F₀ so that string 1 remains vertical is approximately <u>0.377·M·g</u>

<h3>How can the equilibrium of forces be used to find the value of F₀?</h3>

Given:

The weight of the rod = The sum of the vertical forces in the strings

Therefore;

M·g = T₂·cos(37°) + T₁

The weight of the rod is at the middle.

Taking moment about point (2) gives;

M·g × L = T₁ × 2·L

Therefore;

T_1 = \mathbf{\dfrac{M \cdot g}{2}}

Which gives;

M \cdot g = \mathbf{T_2 \cdot cos(37 ^{\circ})+ \dfrac{M \cdot g}{2}}

T_2 = \dfrac{M \cdot g - \dfrac{M \cdot g}{2}}{cos(37 ^{\circ})}  = \mathbf{\dfrac{M \cdot g}{2 \cdot cos(37 ^{\circ})}}}

F₀ = T₂·sin(37°)

Which gives;

F_0 = \dfrac{M \cdot g \cdot sin(37 ^{\circ})}{2 \cdot cos(37 ^{\circ})}} = \dfrac{M \cdot g \cdot tan(37 ^{\circ})}{2}  \approx  \mathbf{0.377  \cdot M \cdot g}

  • F₀ ≈ <u>0.377·M·g</u>

<u />

Learn more about equilibrium of forces here:

brainly.com/question/6995192

3 0
2 years ago
Read 2 more answers
You are pushing on a heavy desk with a force of 65 N the desk does not slide the force of friction between the desk and the floo
astra-53 [7]

When an object does not move even on pushing , static frictional force acts on in opposite direction of the applied force to stop the object from moving. static frictional force is a self adjusting force and it adjust its value according to the applied force if the applied force is smaller than the maximum value of static frictional force. The object starts moving once the applied force on it becomes greater than the maximum static frictional force.  hence the statement is true.

7 0
3 years ago
The recommended adult dose of elixophyllin, a drug used to treat asthma, is 6.00 mg/kg of body mass. calculate the dose in milli
andreev551 [17]

For a 166-lb person, a dose of 452 milligrams is prescribed to treat asthma.

<h3>How would you define asthma?</h3>

Lung damage is a side effect of asthma. Repeated episodes of coughing, dyspnea, chest tightness, and wheezing are also brought on by it. By taking medication and avoiding the triggers that can set off an attack, asthma can be managed. Outdoor allergens, such as pollen from grass, trees, and weeds, are common asthma triggers. Different allergens and irritants might function as triggers for different people. Dust mites, cockroaches, mold, and pet dander are examples of indoor allergies. Air irritants like smoke, chemical fumes, and powerful scents.

Mass = 166 lb×(453.59 g/1 lb)×(1kg/1000g)=75.30 kg

Dose = 75.30 kg ×(6.00 mg/1 kg)=452 mg

Elixophyllin has a 452 mg dose for a 166 lb person with asthma.

To know more about asthma, click here:

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#SPJ4

8 0
1 year ago
Which of the following is the same in all frames of reference?
Ksju [112]
The correct option is B.
The length of an object, the mass of an object and the rate of time passage for an object can change depending on the situation which the object is subject to. For instance in space, the mass and the velocity of an object usually change. But, the value of the speed of light in the space is the same for all observers regardless of the motion of an object, that is, the speed of light is a constant.<span />
4 0
3 years ago
4. A family leaves from New York City and is flying to Los Angles which is 2800mi away. It takes
Blizzard [7]

The average speed of the whole travel is equal to <u>400 mph</u>.

Why?

From the statement, we know that whole travel is divided into three parts. For the first part (traveling from New York to Chicago), we have that it was 3.25 hours and the covered distance was half of the total distance (1400mi). For the second part, we have that it was 1 hour (layover time), and the covered no distance. For the third part (traveling from Chicago to Los Angeles), we have that it was 2.75 hours, and it took the other half of the total distance (1400mi).

We can calculate the average speed of the whol travel using the following formula:

AverageSpeed=\frac{distance_{1}+distance_{2}+distance_{3}}{time_{1}+time{2}+time_{3}}

Now, substituting and calculating, we have:

AverageSpeed=\frac{1400mi+0mi+1400mi}{3.25h+1h+2.75h}

AverageSpeed=\frac{2800mi}{7h}=400mph

Hence, we have the average speed of the whole travel is equal to 400 mph.

Have a nice day!

7 0
3 years ago
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