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Sophie [7]
3 years ago
8

A 9.0 m long uniform rod with a weight of 8 N has 3 masses hanging from it; a 4N mass 1 meter from the left end, a 2 N mass 6 me

ters from the left end and a 3 N mass 4 meters from the left end. What force must be applied to bring the rod into total mechanical equilibrium
Physics
1 answer:
sweet-ann [11.9K]3 years ago
7 0

Answer:

Explanation:

Assume the rod is horizontal

Sum vertical forces to zero

F - 8 - 4 - 2 - 3 = 0

F = 17 N

While this result answers precisely the question asked, it is not sufficient to guarantee equilibrium. We must also locate this force by summing moments to zero. Let's choose to sum about the left end.

8[9/2] + 4[1] + 2[6] + 3[4] - 17[x] = 0

x = 3.76470588...

the force must be supplied upward approximately 3.765 m from the left end

The rod does not actually have to be horizontal. Moment arms will all be proportionately reduced by tilting the bar from horizontal and the results will be identical. Assuming horizontal just reduces the calculation effort.

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An infinite long straight wire is uniformly charged, the charge density is a. Use Coulomb's law to calculate the electric field
bixtya [17]

Answer:

\vec{E} = \frac{a}{2\pi \epsilon_0 R}\^R

Explanation:

Since the wire is infinitely long, we will use Gauss' Law:

\int\vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}

We will draw an imaginary cylindrical surface with height h around the wire. The electric flux through the imaginary surface will be equal to the net charge inside the surface.

In that case, the net charge inside the imaginary surface will be the portion of wire with height h. Then the charge of that portion will be equal to

Q_{enc} = ah

The left-hand side of the Gauss' Law is the flux through the imaginary surface. Since we choose our surface as a cylinder, of which we know the area, we do not have to take the surface integral.

\int\vec{E}d\vec{a} = E2\pi R h

where R is the radius of the imaginary cylinder.

Finally, Gauss' Law gives

E2\pi Rh = \frac{ah}{\epsilon_0}\\E = \frac{a}{2\pi \epsilon_0 R}

The vector expression is

\vec{E} = \frac{a}{2\pi \epsilon_0 R}\^R

As you can see, the electric field is independent from the height h, since that is merely an imaginary cylinder to apply Gauss' Law. In the end, what matters is the charge density of the wire and the distance from the wire.

4 0
4 years ago
What is the acceleration of a 150 kg object pushed with a force of 1000 N?
kirill115 [55]

Answer:

<h2>6.67 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{1000}{150}   \\  =  6.66666..

We have the final answer as

<h3>6.67 m/s²</h3>

Hope this helps you

8 0
3 years ago
After t hours a freight train is s(t) = 18t2 − 2t3 miles due north of its starting point (for 0 ≤ t ≤ 9). (a) Find its velocity
BartSMP [9]

Answer:

Explanation:

Given the equation modelled by the height of the train given as:

s(t) = 18t²-2t³ for for 0 ≤ t ≤ 9

a) Velocity is the rate of change of displacement.

Velocity = dS(t)/dt

V = dS(t)/dt = 36t - 6t² miles

Velocity at t = 3hrs is determiner by substituting t = 3 into the velocity function.

V = 36(3) -6(3)²

V= 108 - 72

Velocity = 36mi/hr

b) for Velocity at time = 7hrs

V(7) = 36(7) - 6(7)²

V(7) = 252 - 294

V(7) = -42mi/hr

The velocity at t = 7hrs is -42mi/hr

c) Acceleration is the rate of change of velocity.

a(t) = dV(t)/dt

Given v(t) = 36t - 6t²

a(t) = 36 - 12t

Acceleration at t=1 is given as:

a(1) = 36 -12(1)

a(1) = 24mi/hr²

4 0
3 years ago
A sample of nitrogen occupies 5.50 liters under a pressure of 900 torr at 25oC. At what temperature will it occupy 10.0 liters a
vitfil [10]

Answer:

<u>At 268.82°C</u> volume occupied by nitrogen is 10 liters at pressure of 900 torr.

Explanation:

Given:

Volume of a sample of nitrogen = 5.50 liters

Pressure = 900 torr

Temperature = 25°C

To find the temperature at which the nitrogen will occupy 10 liters volume at same pressure.

Solution:

Since the pressure is kept constant, so we can apply the temperature-volume law also called the Charles Law.

Charles Law states that the volume of a gas held at constant pressure is directly proportional to the temperature of the gas in Kelvin.

Thus, we have :

V ∝ T

\frac{V}{T}=k

where k is a constant.

For two samples of gases, the law can be given as:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

From the data given:

V_1=5.5\ l

T_1=25\ \°C =(273+25)K= 298 K

V_2=10\ l

We need to find T_2.

Plugging in values in the formula.

\frac{5.5}{298}=\frac{10}{T_2}

Multiplying both sides by T_2.

T_2\times\frac{5.5}{298}=\frac{10}{T_2}\times T_2

\frac{5.5}{298}T_2={10}

Multiplying both sides by \frac{298}{5.5}

\frac{298}{5.5}\times\frac{5.5}{298}T_2=\frac{10\times 298}{5.5}

T_2=541.82\ K

T_2=541.82\ K-273\ K = 268.82\°C

Thus, at 268.82°C volume occupied by nitrogen is 10 liters at pressure of 900 torr.

7 0
3 years ago
The diagram below shows two electromagnetic waves.
zaharov [31]
The best C) Wave 1 is generated by electric circuits and wave 2 is emitted by radioactive material. 

The higher frequency waves will be radioactive material, while the electromagnetic radiation generated by circuits will have a much lower frequency. 
3 0
4 years ago
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