All categories

3 years ago

An object of mass 82kg is accelerated upward at 3.2m/s/s. what force is required

Physics

1 answer:

vampirchik [111]3 years ago

6 0

F = m · a

In order to accelerate 82 kg upward at the rate of 3.2 m/s², a NET upward force of (82kg · 3.2m/s²) = 262.4 Newtons is required.

But if the object is on or near the surface of the Earth, then there's a downward force of (82kg · 9.8m/s²) = 803.6 N already acting on it because of gravity.

So you need to apply (803.6N + 262.4N) = <em>1,066 Newtons UPward</em>, in order to cancel its own weight and accelerate it upward at that rate.

You might be interested in

This problem has been solved!See the answerCommunication with submerged submarines via radio waves is difficult because seawater

mash [69]

Answer:

4000 km

Explanation:

as we know velocity of electromagnetic wave is c

$c = 3 * 10^8 m/s$

frequency given (f) = 76 Hz

wavelength ?

using

$c =f$ λ

λ = $\frac{c}{f}$

λ = $\frac{3 * 10^8}{76}$ ≈4000 km

so final answer λ = 4000km

8 0

3 years ago

Before the positive psychology movement, psychology focused mainly on

KonstantinChe [14]

Before positive psychology, the main focus was mostly pathology, that is, studying various psychological issues and sometimes finding ways to treat them, or sometimes not and just studying them for the sake of studying them and noting their occurrence.

7 0

3 years ago

Read 2 more answers

Two parallel wires carry a current I in the same direction. Midway between these wires is a third wire, also parallel to the oth

Luda [366]

Answer:

Force is repulsive hence direction of force is away from wire

Explanation:

The first thing will be to draw a figure showing the condition,

Lets takeI attractive force as +ve and repulsive force as - ve and thereafter calculating net force on outer left wire due to other wires, net force comes out to be - ve which tells us that force is repulsive, hence direction of force is away from wire as shown in figure in the attachment.

4 0

3 years ago

Read 2 more answers

A person pushes a large 42.9 kg box at a constant velocity of 9 m/s across a horizontal floor for 3.8 s. Find the

Gwar [14]

Answer:

10 kJ

Explanation:

W = Fd

W = (μN)(vt)

W = μ(mg)vt

W = 0.7(42.9)(9.81)(9)(3.8)

W = 10,075.12506 J

W ≈ 10 kJ

6 0

3 years ago

Chord progressions that move to resting points that release tension are called

Sav [38]

Cadences.

These cadences are the resulting tensions that chords release from their resting points. This movement is classified from a unstable chord progression to a stable one. Thank you for your question. Please don't hesitate to ask in Brainly your queries.

6 0

3 years ago