A hanging mass of 23 kg will exert a force of:
23 * 9.81 = 225.6 Newtons on the string
Thus, during rotation, the force exerted should remain less than this. Force on an object in circular motion is given by:
F = (m * v^2) / r
225.6 = (2.95 * v^2) / 0.791
v = sqrt(60.491)
v = 7.78 m/s
Thus, the magnitude of the velocity should not exceed 7.78 meters per second.
I listen to bring the madness it relaxes me a lot and also knock knock knock FBI open up
It’s the velocity, meter/second
540 nonlillion
thats a 540 followed by 30 0's
Answer:
Deceleration = 5.7 m/s²
Explanation:
We are given;
Deceleration of the car; d = -3.15 m/s²
Angle of inclination; θ = 9.7°
Coefficient of friction will be calculated as; μ = d/g = 3.15/9.81 = 0.3211
Now,the acceleration would be gotten from the formula;
a = g (sin(θ) + μ cos(θ))
Plugging in the relevant values to give;
a = 9.81[sin 9.7 + (0.3211 × cos (9.7)]
sin 9.7 and cos 9.7 are in radians, thus we have;
a = 9.81(-0.2718 + (0.3211 × -0.9624))
a = -5.7 m/s²
Negative acceleration means a Deceleration of 5.7 m/s²