Answer:
23. 4375 m
Explanation:
There are two parts of the rocket's motion
1 ) accelerating (assume it goes upto h1 height )
using motion equations upwards
Lets find the velocity after 2.5 seconds (V1)
V = U +at
V1 = 0 +5*2.5 = 12.5 m/s
2) motion under gravity (assume it goes upto h2 height )
now there no acceleration from the rocket. it is now subjected to the gravity
using motion equations upwards (assuming g= 10m/s² downwards)
V²= U² +2as
0 = 12.5²+2*(-10)*h2
h2 = 7.8125 m
maximum height = h1 + h2
= 15.625 + 7.8125
= 23. 4375 m
Answer:
Its simple! B The ball accelerates upward!♡♡
Answer:
<u><em>Electric Potential Energy:</em></u>
The energy that is needed to move a charge against an electric firld is called Electric Potential Energy
<u><em>Electric Potential Difference:</em></u>
The amount of work done in carrying a unit charge from one point to an other in an electric field is called Electric Potential Difference.
<u><em>Relation:</em></u>
Relation between Electric potential and electrical potential energy is given by
Here PE represents Electric potential energy
and 
is Electric potential difference
it means electric potential difference is the difference in electric potential energy divided by the charge.
No because it will contain the same amount of mass, just in different forms.
Explanation:
Assuming we can turn on the lightbulb from any distance with a device. We can gradually increase the distance that separates us from lightbulb, in this way, if the speed of light is finite we can see a temporary delay between the moment we turn on the lightbulb and the moment in which we observe its light.
