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Ainat [17]
3 years ago
7

How many triangles can be constructed with angles measuring 10°, 30°, and 90° ?​

Mathematics
2 answers:
coldgirl [10]3 years ago
6 0

Answer:

There are an infinite number of triangles which can be constructed with angles measuring this.

There are an infinite number of lengths the sides of the triangles can be while the angles stay the same measur

Archy [21]3 years ago
4 0
Is there a picture? To it
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What is the product of 8x-3 and x2- 4x +8
Dmitriy789 [7]
A product is the answer that you get when you multiply numbers together. So for this problem, you have 2 groups to multiply together. Since I cannot show a square or cubed x, I will put an x2 for x squared and an x3 for x cubed. You have to multiply each number in the first parentheses by each number in the second parentheses. Then combine any like sets.

(8x-3)(x2-4x+8)
8x3-32x2+64x-6x+12x-24
8x3-32x2+70x-24

So the answer is 8x cubed minus 32x squared plus 70x minus 24. Whew! That's a long one. Hope I didn't miss anything.
5 0
3 years ago
The measure of position called the midquartile of a data set is found using the formula StartFraction Upper Q 1 plus Upper Q 3 O
irinina [24]

Answer:

35.25

Step-by-step explanation:

Give the data set:

23 37 49 34 35 41 40 26 32 22 38 42

We are expected to calculate the midquartile of the given data set.

22 23 26 32 34 35 37 38 40 41 42 49

First step is to find the lower quartile which comprises of

22 23 26 32 34 35

Here the Q1 is (26+32)/2 = 58/2= 29

Second step to find the upper quartile which comprises of

37 38 40 41 42 49

Here the Q3 is (40+41) /2 = 81/2 = 41.5

Then to find the midquartile which is (Q1+Q3) /2 where Q1 is 29 and Q3 is 41.5

= (29+41.5)/2

= (70.5) /2 = 35.25

8 0
3 years ago
I need help quick. I will mark as brainliest.​
Dimas [21]

Answer:

The slope is -5x

Step-by-step explanation:

To find the slope, you do rise/run. So to get from one point to the other, you would move 5 units down, and 1 unit to the right.

It can be written as -5/1 or -5.

Hope this helps!

8 0
3 years ago
Please help me with finding both area and perimeter of the shape.
VladimirAG [237]
Perimeter=106ft
Area=448ft^2

Make sure you remember to subtract various values to find the length of missing sides.
6 0
3 years ago
The test scores on a 100-point test were recorded for 20 students:71 93 91 86 7573 86 82 76 5784 89 67 62 7277 68 65 75 84a. Can
Dafna11 [192]

Answer: a. Yes

              b. mean = 76.65

                  standard deviation = 10.04

              c. 76.65 ± 4.4

Step-by-step explanation:

a. <u>Stem</u> <u>and</u> <u>leaf</u> <u>Plot</u> shows the frequencies with which classes of value occur. To create this plot, we divide the set of numbers into 2 columns: <u>stem</u>, the left column, which contains the tens digits; <u>leaf</u>, the right column, which contains the unit digits.

<u>Normal</u> <u>distribution</u> is a type of distribution: it's a bell-shaped, symmetrical, unimodal distribution.

A stem and leaf plot displays the main features of the distribution. If turned on its side, we can see the shape of the data.

The figure below shows the stem and leaf plot of the 100-point test score. As we can see, when turned, the plot resembles bell-shaped distribution. So, this test scores were selected from a normal population.

b. <u>Mean</u> is the average number of a data set. It is calculated as the sum of all the data divided by the quantity the sample has:

mean = \frac{\Sigma x}{n}

For the 100-point test score:

mean = \frac{71+93+91+...+65+75+84}{20}

mean = 76.65

<u>Standard</u> <u>Deviation</u> determines how much the data is dispersed from the mean. It is calculated as:

s=\sqrt{\frac{\Sigma (x-mean)^{2}}{n-1} }

For the 100-point test score:

s=\sqrt{\frac{[(71-76.65)+(93-76.65)+...+(84-76.65)]^{2}}{20-1} }

s = 10.04

The mean and standard deviation of the scores are 76.65 and 10.04, respectively.

c. <u>Confidence</u> <u>Interval</u> is a range of values we are confident the real mean lies.

The calculations for the confidence interval is

mean ± z\frac{s}{\sqrt{n} }

where

z is the z-score for the 95% confidence interval, which is equal 1.96

Calculating interval

76.65 ± 1.96.\frac{10.04}{\sqrt{20} }

76.65 ± 4.4

The 95% confidence interval for the average test score in the population of students is between 72.25 and 81.05.

7 0
3 years ago
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