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victus00 [196]
3 years ago
12

Giving brainlist to whoever answers

Mathematics
1 answer:
never [62]3 years ago
3 0

Answer:

I think the answer would be -5

Step-by-step explanation:

Sorry if its wrong

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Solve the system of equations below algebraically <br> 2x+3y=6 and -5x+2y=4
Charra [1.4K]


Steps
I’m using elimination so I’m trying to get rid of y
To do that I multiply the first equation by 2 and the second by -3. Then solve
4x + 6x = 12
15x + -6x = -12
—————————
19x + 0 = 0
Divid by 19 to get x to one side. 0/19 is 0 so
X= 0
Plug that into an equation so 0 + 3y = 6
Divid by 3 and y = 2
Answer x = 0 y = 2
7 0
3 years ago
Help I’m so confused
velikii [3]

Answer:

5x: linear; monomial

-7: constant; monomial

x^2 + 4: quadratic, binomial

x^2 - 3x + 11: quadratic, trinomial

2x - 9: linear, binomial

Step-by-step explanation:

Name using degree: just count the highest number of variables in a single term. if it's 0, its a constant polynomial, if it's 1 it's linear, 2 quadratic, 3 cubic

Name using number of terms: just count the number of "things" added or subtracted. If there's one, it's a monomial, two: binomial, three: trinomial.

6 0
2 years ago
A short time after a skydiver jumps out of am airplane
murzikaleks [220]

Answer:then what?

Step-by-step explanation:

3 0
3 years ago
The figure shows triangle ABC with medians AF, BD, and CE. Segment AF is extended to H in such a way that segment GH is congruen
attashe74 [19]

Answer: Segment GD is parallel to segment HC.

Step-by-step explanation:

In ΔAHC

AG=GH (given)...........1

As BD is the median of ΔABC bisecting AC at D

∴AD=DC.........2

⇒\frac{AD}{DC}=\frac{AG}{GH}=1(from 1 and 2)

⇒segment GD is dividing the sides AH and AC  in same ratio.

Therefore by the converse of Basic proportionality theorem,segment GD is parallel to segment HC.

Converse of basic probability theorem states that if a line divides any two sides of a triangle in the same ratio, then the line must be parallel to the third side.

5 0
3 years ago
Read 2 more answers
Javier has four cylindrical models. The heights, radii, and diagonals of the vertical cross-sections of the models are shown in
Ronch [10]

The model in which the lateral surface meets the base at right angle is : Model 1.

<h3>What is a lateral surface?</h3>

The lateral surface of an object is all surfaces  of that object excluding its base and top.

Analysis:

To know the exact model, we check for the models in which their dimensions form a Pythagorean triplet otherwise a right-angled triangle.

For Pythagorean triplet, the square of the diagonal must be equal to the sum of squares of the other two sides.

Model 1

Diagonal = 50cm, radius = 14cm, lateral height = 48cm

(50)^{2} = (14)^{2} + (48)^{2}

2500 = 196 + 2304

2500 = 2500. Forms Pythagorean triplet

Model 2

Diagonal= 37cm, radius = 6cm  lateral height = 35cm

(37)^{2} = (35)^{2}+ (6)^{2}

1369 = 1225 +36

1369 \neq 1261

Model 3

Diagonal = 60cm, radius = 20cm  lateral height = 40cm

(60)^{2} = (20)^{2} + (40)^{2}

3600 = 400 + 1600

3600 \neq 2000

Model 4

Diagonal = 30cm, radius = 24cm, lateral height = 9cm

(30)^{2} = (24)^{2} + (9)^{2}

900 = 576 + 81

900 \neq 657

Therefore the lateral surface model 1 meets the base at right angle

In conclusion,  the lateral surface of model 1 meets the base at right angles as the dimensions form a right-angled triangle.

Learn more about Pythagorean triplet: brainly.com/question/20894813

#SPJ1

5 0
2 years ago
Read 2 more answers
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