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Tomtit [17]
3 years ago
13

I really need help on this

Mathematics
1 answer:
arlik [135]3 years ago
6 0

Answer:

(x+2, y-6)

answer C

Step-by-step explanation:

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PLease solve for n I dont know how to do it
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Answer:

37

Step-by-step explanation:

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3 years ago
Simply 7/4 squared ​
klemol [59]

Answer:

0.4375

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5 0
3 years ago
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Which of the lines graphed in the diagram represents the equation 6x + 4y = 8
Blizzard [7]
In order to easily discern which graph is a proper representation of 6x + 4y = 8, you first need to convert the equation to y = mx+ b, also known as slope-intercept form. Here's how you can do this:
6x + 4y = 8
4y = -6x + 8
y = -1.5x + 2
The +2 tells you that your line will intercept the vertical y-axis at (0, 2). This narrows it down to graphs a and d. Then, because you have a NEGATIVE number in front of your x (it's -1.5), you can tell that your graph will be going down as it moves from left to right. This leaves you with graph d as your answer!
6 0
3 years ago
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Using a multiple of ten for at least one factor write an equation with a product that has four zeros
PtichkaEL [24]

Answer:

The required equation is : 5 · 4000 = 20,000

Step-by-step explanation:

We have to use multiple of 10 for at least one factor.

So, in order to form our equation, we take one factor as 4000 which is a multiple of 10 (10 × 400 = 4000)

And the other condition to form the equation is given that the product should contain 4 zeros, so we need to multiply the first factor 4000 by some number such that the product contains 4 zeros.

Therefore, if we multiply 4000 by 5 we get the product as 20000 which contains 4 zeros.

Hence, 5 × 4000 = 20,000 is our required equation.

8 0
3 years ago
Help please!! i don’t understand this one!
12345 [234]

Answer:

  C, D

Step-by-step explanation:

This equation can be solved any of several ways. One that doesn't require much thought is using the quadratic formula.

For ax² +bx +c = 0, the solutions are ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

In the given equation, a=2, b=11, c=5, so this becomes ...

  x=\dfrac{-11\pm\sqrt{11^2-4\cdot2\cdot5}}{2\cdot2}=\dfrac{-11\pm\sqrt{81}}{4}\\\\x=\dfrac{-11\pm9}{4}=\left\{-\dfrac{20}{4},-\dfrac{2}{4}\right\}=\{-5,-\frac{1}{2}\}

The solutions are ...

  C. x = -5

  D. x = -1/2

_____

My personal favorite is using a graphing calculator. The solutions are the x-intercepts of the expression on the left. That is, where its value is zero, as the equation says.

5 0
3 years ago
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