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I am Lyosha [343]
3 years ago
5

For each statement below, indicate whether it is true or false.

Biology
1 answer:
Lynna [10]3 years ago
6 0

1. True

Organisms must have at least one cell to be considered living things. Virus are not included here.

2. False

All cells has the same DNA

3. True

Estudos recentes têm apontado que todos os seres vivos tenham evoluído de um único antepassado, no caso da teoria de Thomas Cavalier-Smith, seriam os coanoflagelados, um grupo de protistas.

4. True

DNA for example is a universal molecule, even in different organisms, it maintains its same function as that of "making" proteins needed for the cells of individuals.

5. False

The diversity of life is explained by de biodiversity, that is caused by DNA mutations, environmental pressure and the natural selection.

6. False

Informations are stored in organic molecules, like DNA

7. True

The environment can also cause our cells to process information. An example: In a sexual relationship, the environment (which is the situation) causes our body to release high levels of hormone (testosterone) that raise our heart rate and blood pressure.

8. False

Organisms are not closed systems, but open systems.

9. True

Homeostasis is the ability to maintain the internal environment in an almost constant equilibrium, regardless of changes occurring in the external environment. It is possible because of the elaborate signaling networks that exists between different cells within an organism.

10. False

Evolutionary change arises the unity of living systems

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A man and a woman are both carriers for two autosomal recessive disorders, PKU (chromosome 12) and cystic fibrosis (chromosome 7
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Answer:

Pr= (3/16)

Explanation:

It was stated that both the man and the woman are both carriers for two autosomal recessive disorders, PKU (chromosome 12) and cystic fibrosis (chromosome 7).

∴ let Aa¹Bb° represent the traits in the Man

Where;

Aa¹ = carrier of PKU

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Also, let Cc¹Dd° represent the traits in the woman

Where;

Cc¹ = carrier of PKU

Dd° = carrier of cystic fibrosis

Now, if Aa¹Bb° self-crossed, we'll have the F1 progeny as AB, Ab° , a¹B and a¹b°

also, if Cc¹Dd° self-crossed, we have CD, Cd° , c¹D and c¹d° as their F1 progeny

In the F2 generation, the dihybrid cross between the F1 generations will be:

AB, Ab° , a¹B, a¹b°    × CD, Cd° , c¹D, c¹d°

ACBD, ACb°D, a¹CBD, a¹Cb°D

ACBd°, ACb°d°, a¹CBd°, a¹Cb°d°

Ac¹BD, Ac¹b°D, a¹c¹BD, a¹c¹b°D

Ac¹Bd°, Ac¹b°d°, a¹c¹Bd°, a¹c¹b°d°

Only (a¹CBD, Ac¹BD, a¹c¹BD)  shows the probability that she will have PKU but not CF.

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