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defon
3 years ago
5

Plz answer only if you know it's correct. willl give brainliest to best answer

Mathematics
2 answers:
alexira [117]3 years ago
7 0

Answer: slope = 3/2

brainliest plz

Step-by-step explanation:

just olya [345]3 years ago
3 0

Answer:

i believe is is 3/2

Step-by-step explanation:

as y goes up 30 x goes over 20

30/20 simplified is 3/2

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over three successive Collins build 1/3, 1/5 and 1/4 of the brickwork of his new garage. What fraction must he complete on the f
garri49 [273]

Answer:

1 - 1/3 - 1/4 - 1/5

Step-by-step explanation:

Let's take it one step at a time.

Day 1 he completes 1/3 of the garage, so you subtract 1/3 from 1 which means he left 2/3

Day 2 he completed 1/4 more, so you again subtract, this time though 2/3 - 1/4, or in other words 1 - 1/3 - 1/4

So you do this one more time.  1 - 1/3 - 1/4 - 1/5

Can you handle this or do you need help with fraction subtraction.  

5 0
3 years ago
Using the results from a survey of 1050 elibible voters, an approximate 98% confidence interval estimate for the proportion of v
Soloha48 [4]

Answer: p= 0.644

Step-by-step explanation:

We know that, the confidence interval for population proportion is given by :-

sample proportion(p) ± Margin of error(E)

Given confidence interval :  (0.61,0.678)

i.e. p- E = 0.61   ... (i)

p+E = 0.678    ...(ii)

Adding (i) and (ii), we get

2p = 1.288

p= 0.644

From (ii),

E= 0.678-0.644

E= 34

Hence, the value of p = 0.644

3 0
3 years ago
Use the dots for one and two. what is the difference between the ranges
sergij07 [2.7K]

Answer:

a. 20 points

Step-by-step explanation:

Range = Largest given value - Smallest given value.

<u>Identifying the range of test 1</u>

Looking at the dot plot the lowest test grade appears to be 50 while the highest is 90.

So range of test 1 = 90 - 50 = 40

<u>Identifying the range of test 2</u>

Looking at the plot the lowest test grade appears to be 40 while the highest appears to be 100

So range = 100 - 40 = 60

<u>Identifying the differences between the ranges</u>

Test 1 range : 40

Test 2 range : 60

Difference between the two : 60 - 40 = 20 points

6 0
2 years ago
Jean throws a ball with an initial velocity of 64 feet per second from a height of 3 feet. Write an equation and answer the ques
Ganezh [65]
<h2>a. What is your equation?</h2>

This is a problem of projectile motion. A projectile is an object you throw with an initial velocity and whose trajectory is determined by the effect of gravitational acceleration. The general equation in this case is described as:

h(t)=-\frac{1}{2}gt^2+v_{0}t+h_{0}

Where:

h(t): \ height \ at \ any \ time \\ \\ g: \ acceleration \ due \ to \ gravity \ 9.8m/s^2 \ or \ 32.16ft/s^2 \\ \\ v_{0}= \ Initial \ velocity

So:

v_{0}=64ft/s \\ \\ h_{0}=3ft

Finally, the equation is:

h(t)=-\frac{1}{2}(32.16)t^2+(64)t+3 \\ \\ \boxed{h(t)=-16.08t^2+64t+3}

<h2>b. How long will it take the rocket to reach its maximum height?</h2>

The rocket will reach the maximum height at the vertex of the parabola described by the equation h(t)=-16.08t^2+64t+3. Therefore, our goal is to find t at this point. In math, a parabola is described by the quadratic function:

f(x)=ax^2+bx+c

So the x-coordinate of the vertex can be calculated as:

x=-\frac{b}{2a}

From our equation:

a=-16.08 \\ \\ b=64 \\ \\ c=3

So:

t=-\frac{64}{2(-16.08)} \\ \\ \boxed{t=1.99s}

So the rocket will take its maximum value after 1.99 seconds.

<h2>c. What is the maximum height the rocket will reach?</h2>

From the previous solution, we know that after 1.99 seconds, the rocket will reach its maximum, so it is obvious that the maximum height is given by h(1.99). Thus, we can find this as follows:

H_{max}=h(1.99)=-16.08(1.99)^2+64(1.99)+3 \\ \\ \boxed{H_{max}=66.68ft}

So the maximum height the rocket will reach is 66.68ft

<h2>d. How long is the rocket in the air?</h2>

The rocket is in the air until it hits the ground. This can be found setting h(t)=0, so:

0=-16.08t^2+64t+3 \\ \\ Applying \ quadratic \ formula: \\ \\ t_{12}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=-16.08 \\ \\ b=64 \\ \\ c=3 \\ \\ t_{12}=\frac{-64 \pm \sqrt{64^2-4(-16.08)(3)}}{2(-16.08)} \\ \\ t_{1}=4.0264 \\ \\ t_{2}=-0.046

We can't have negative value of time, so the only correct option is t_{1}=4.0264 and rounding to the nearest hundredth we have definitively:

\boxed{t=4.03s}

3 0
4 years ago
Lesson 1: identify pairs of lines and angles draw two lines intersected by a transversal. label corresponding angles ∠1 and ∠2.
Travka [436]
Each number goes by tge side ??
6 0
4 years ago
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