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2 years ago

Which equation is true? *

Mathematics

2 answers:

Fudgin [204]2 years ago

7 0

The answer it’s A i used a calculator

GarryVolchara [31]2 years ago

4 0

The answer would be a.

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7 times the number of cookies in the jar plus 5 more from the tray is 54. How many cookies are in the jar?

Digiron [165]

Answer:

The number of cookies in the jar is 7.

If we include the 5 cookies from the tray in the jar the total number of cookies would be 5 + 7 = 12

Step-by-step explanation:

Consider the number of cookies in the jar as 'x'. Hence the equation formed would be:-

7(x) + 5 = 54

7x + 5 = 54

7x = 54 - 5

7x = 49

x = $\frac{49}{7}$

x = 7

The number of cookies in the jar is 7.

If we include the 5 cookies from the tray in the jar the total number of cookies would be 5 + 7 = 12

Hope this helps.

8 0

2 years ago

Karl's car went 550 miles on 33 gallons of gas. Which equation does NOT give the correct unit rate, x, in miles per gallon for K

jekas [21]

Answer:

x = 550 ÷ 33

what are the answer choises

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which situations can be presented by an exponential function?

Evgesh-ka [11]

Answer:

It’s C and D I just finished the text and finished with 100% thanks to the person in the comments in the question below

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A man is in a boat 2 miles from the nearest point on the coast. He is to go to point Q, located 3 miles down the coast and 1 mil

mafiozo [28]

Answer:

The answer is "0.45385".

Step-by-step explanation:

The time is taken to reach the coast $= \frac{\sqrt{(2^2 + x^2)}}{4}$

The time is taken to reach Q after reaching the coast $= \frac{\sqrt{(1 + (3-x)^2)}}{4}$

Total time, $T= \frac{\sqrt{(1 + (3-x)^2)}}{4}+ \frac{\sqrt{(1 + (3-x)^2)}}{4}$

This has to be minimum,

$\to \frac{dt}{dx} = 0$

$\to \frac{\sqrt{(2^2 + x^2)}}{2} + \frac{\sqrt{1 + (3-x)^2}}{3}\\\\ \frac{x}{4}\sqrt{(4+x^2)} + \frac{(x-3)}{(4\sqrt{(x^2-6x+10)}} = 0\\\\\frac{x^2}{16} \times (4+x^2) = \frac{(x-3)^2}{16 \times (x^2-6x+10)}\\\\x^2(4+x^2) = \frac{(x-3)^2}{(x^2-6x+10)}\\\\4x^2+x^4 = \frac{ x^2+9-6x}{(x^2-6x+10)}\\\\ 4x^2+x^4(x^2-6x+10) = x^2+9-6x\\\\4x^4-24x^3+40x^2+x^6-6x^5+10x^4= x^2+9-6x\\\\x^6-6x^5+ 14x^4-24x^3+39x^2+6x-9=0\\\\$

x=0.45385

6 0

3 years ago

The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero. proc

Delvig [45]

Coding the given algorithm in python 3, the greatest common divisor of the values (124 and 244) and (4424 and 2111) are 4 and 1 respectively.

The program implementation goes thus :

def gcd(a, b):

#initialize a function named gcd which takes in two parameters

if a>b:

#checks if a is greater than b

return gcd (b, a)

#if true interchange the Parameters and Recall the function

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

#even numbers leave no remainder when divided by 2, checks if a and b are even

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

#checks if a is odd and B is even

return gcd(a, b/2)

else :

return gcd(a, b-a)

A sample run if the program on the values given :

print(gcd(124, 244))

print()

#leaves a space after the first output

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

8 0

2 years ago