Answer:
Option D. 5.45 Ω
Explanation:
From the question given above, the following data were obtained:
Resistance 1 (R₁) = 10 Ω
Resistance 2 (R₂) = 20 Ω
Resistance 3 (R₃) = 30 Ω
Voltage (V) = 120 V
Equivalent resistance (R) =?
The equivalent resistance can be obtained as follow:
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/10 + 1/20 + 1/30
Find the least common multiple (lcm) of 10, 20 and 30. The result is 60
Divide 60 by each of the denominators and multiply by their numerators respectively. We have:
1/R = (6 + 3 + 2)/60
1/R = 11/60
Invert
R = 60/11
R = 5.45 Ω
Thus, the equivalent resistance in the circuit is 5.45 Ω
Answer:
Stop watch
Stop clock
Explanation:
Absolute time is time measured in definite periods such as minutes, days, and years. It can be measured uising stop watch or stop clock
Answer:
AB = 29
Explanation:
For a better understanding, we must work this problem in a graphic way. In the attached image we can see the solution.
First, we draw a vertical dotted lines from the point J & K to the line ML, then we can see two new portions with the same length. Then with this simple analysis:
2x = 39 - 19
x = 10
Then we know that x = 10, another important data to find the answer is that the AB line is located in the midpoints of the legs. We also can see the right triangle MJ and the dotted line.
Now for every single right triangle, no matter its size and relationship between the vertical and the horizontal lengths, if some point is located in the hypotenuse (leg) at the middle of its length. This will be proportional to the vertical and the horizontal cathetus, therefore we will have the middle point on those two lines.
So, the AB line will be the sum of JK plus two times 5
AB = 19 + 5 + 5 = 29
X - Xo = 0.5(Vo +V)t
Xo cancels because it is 0 (she is at rest)
17 = 0.5(0+V)3.8
17 = 1.9V
Final velocity is 8.94737 m/s
The stomach is above the waist, below the waist is your, yunno. the stomach and bladder sit right on top of the waist, hope this helps, have an amazing day:)