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yuradex [85]
2 years ago
7

Car B is being pushed by a force of 22000 N. If it has a mass of 1375 kg.,

Physics
1 answer:
Burka [1]2 years ago
5 0

Answer:

a = 16 m/s²

General Formulas and Concepts:

<u>Dynamics</u>

Newton's Law of Motions

  • Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion
  • Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)
  • Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction<u> </u>

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] F = 22000 N

[Given] m = 1375 kg

[Solve] a

<u>Step 2: Find Acceleration</u>

  1. Substitute in variables [Newton's 2nd Law of Motion]:                                 22000 N = (1375 kg)a
  2. Isolate <em>a</em>:                                                                                                            16 m/s² = a
  3. Rewrite:                                                                                                             a = 16 m/s²
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Two gliders collide on a frictionless air track that is aligned along the x axis. Glider A has an initial velocity of +4.0 m/s a
DedPeter [7]

Answer:

As collision is elastic,thus we can use conservation of momentum equation

mA=0.2 kg

(vB)1=0 m/s.......................as it is on rest before collision

(vA)1=4 m/s

(vA)2=-1 m/s

(vB)2=2 m/s

using equation

(mA*vA+mB*vB)1= (mA*vA+mB*vB)2

Where 1 and 2 represents before and after collision

(0.2*4)+(mB*0)=(0.2*-1)+(mB*2)

0.8=-0.2+(2mB)

mass of object B=mB=0.3 Kg

6 0
3 years ago
For each statement in the rows, select the most suitable option (words) in the columns. One selection for each row.
Korvikt [17]

Answer:

the answer is most likely likely to be 2

5 0
2 years ago
13. How much work does a 35 N force do to lift a potted plant from the floor to a shelf 6 m high?
Nataly_w [17]

Answer:

W= 210 N

Explanation:

Just use work = Fparallel*d

W= 35*6

W= 210 N

8 0
3 years ago
If the coefficient of kinetic friction between a 22 kg kg crate and the floor is 0.27, what horizontal force is required to move
alina1380 [7]

Answer:

58.27 N

Explanation:

the data we have is:

mass: m=22kg

coefficient of friction: \mu =0.27

and we also know the acceleration of gravity is g=9.81m/s^2

We need to do an analysis of horizontal and vertical forces acting on the object:

-------

Vertically the forces acting on the object:

  • Normal force N (acting up from the object)
  • weight: w=mg (acting down from)

so the sum of forces in the vertical axis "y" are:

F_{y}=N-w\\F_{y}=N-mg

from Newton's second Law we know that F=ma, so:

ma_{y}=N-mg

and since the object is not accelerating in the vertical direction (the movement is only horizontal) a_{y}=0, and:

0=N-mg\\N=mg

-----------

now let's analyze the horizontal forces

  • frictional force: f= \mu N and since N=mg  --> f=\mu mg
  • force to move the object: F

and the two forces just mentioned must be opposite, thus the sum of forces in the "x" axis is:

F=ma_{x}=F-f\\ma_{x}=F-\mu mg

and we are told that the crate moves at a steady speed, thus there is no acceleration: a_{x}=0

and we get:

0=F-\mu mg\\F=\mu mg

substituting known values:

F=(0.27)(22kg)(9.81m/s^2)\\F=58.27N

3 0
3 years ago
The period of a sound wave coming from an instrument is 0. 002 seconds. What is the frequency of the sound? Hz.
Pie

The period is the time taken by the wave to complete an oscillation. The frequency of the given sound is 500 Hz.

<h2>Period:</h2>

It is the time taken by the wave to complete an oscillation. The frequency is inversely proportional to the time:

f = \dfrac 1T

Where,

f- frequency

T - period = 0.002 s

Put the value in the equation,

f = \dfrac 1{0.002}\\\\f = 500\rm \  Hz

Therefore, the frequency of the given sound is 500 Hz.

Learn more about Period:

brainly.com/question/842349

5 0
2 years ago
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