Question

The charge per unit length on a long, straight filament is-92.0 μC/m. (a) Find the electric field 10.0 cm from the filament, where distances are measured perpendicular to the length of the filament. (Take radially inward toward the filament as the positive direction. MN/C (b) Find the electric field 46.5 cm from the filament, where distances are measured perpendicular to the length of the filament. MN/C (c) Find the electric field 130 cm from the filament, where distances are measured perpendicular to the length of the filament. MN/C

Answer 1

Answer:

E(0.1m)=-16.53.10^6 V.m

E(0.465m)=-3.55.10^6 V.m

E(1.3m)=-1.27^6 V.m

Explanation:

You can find the field using Gauss's Law:

$\int\ E.} \, dS = \frac{Qin}{\epsilon }$

the surface S is an "infinite long" cylinderr of radio r.

$\int\ {E.} \, dS = E\int\ dS=E.S=E2\pi rL$

$Qin=\lambda L$

E(r)=$\frac{\lambda }{2\pi \epsilon} . \frac{1}{r}$

λ=-92.0 μC/m, ε=8.85.10^-12

E(0.1m)=-16.53.10^6 V.m

E(0.465m)=-3.55.10^6 V.m

E(1.3m)=-1.27^6 V.m