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seraphim [82]
3 years ago
11

A compact disk with a 12 cm diameter is rotating at 5.24 rad/s.

Physics
1 answer:
musickatia [10]3 years ago
7 0

Answer:

(a) 31.44 m/s (b) 164.74 m/s²

Explanation:

Given that,

The diameter of a disk, d = 12 cm

Radius, r = 6 cm

Angular speed = 5.24 rad/s

(a) Linear speed,

v=r\omega\\\\v=6\times 5.24\\\\v=31.44\ m/s

(b) Centripetal acceleration,

a=\dfrac{v^2}{r}\\\\a=\dfrac{31.44^2}{6}\\\\a=164.74\ m/s^2

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kap26 [50]

Answer:

c she's very clever

Explanation:

5 0
3 years ago
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A block of gelatin is 120mm by 120mm by 40mm whrn unstressed. A force of 49N is applied tangentially to the upper surface causin
Inessa05 [86]

Answer:

The shearing stress is 10208.3333 Pa

The shearing strain is 0.25

The shear modulus is 40833.3332 Pa

Explanation:

Given:

Block of gelatin of 120 mm x 120 mm by 40 mm

F = force = 49 N

Displacement = 10 mm

Questions: Find the shear modulus, Sm = ?, shearing stress, Ss = ?, shearing strain​, SS = ?

The shearing stress is defined as the force applied to the block over the projected area, first, it is necessary to calculate the area:

A = 40*120 = 4800 mm² = 0.0048 m²

The shearing stress:

Ss=\frac{F}{A} =\frac{49}{0.0048} =10208.3333Pa

The shearing strain is defined as the tangent of the displacement that the block over its length:

SS=tan\theta =\frac{Displacement}{L}  =\frac{10}{40} =0.25

Finally, the shear modulus is the division of the shearing stress over the shearing strain:

Sm=\frac{10208.3333}{0.25} =40833.3332Pa

6 0
4 years ago
PLEASE ANYONE CAN HELP ME !E.x/A block of metal has a volume of 0.09 m3
LuckyWell [14K]

Answer:

B = 1058.4  N

Explanation:

Given that,

The volume of a metal block, V = 0.09 m³

The density of fluid, d = 1200 kg/m³

We need to find the buoyant force when it's Completely  immersed in brine. The formula for the buoyant force is given by :

B=\rho gV

g is acceleration due to gravity

B=1200\times 9.8\times 0.09\\\\B=1058.4\ N

So, the required buoyant force is 1058.4  N.

3 0
3 years ago
Part D
Brrunno [24]

Answer:

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i. In the case of two combinations where two ends are the same, it could be observed that the two ends (poles) repels each other. Thus since like poles repels, magnetic force of repulsion is felt.

ii. In the case of one combination in which the two ends are different, the two ends (poles) attract. Since unlike poles attracts, magnetic force of attraction is observed.

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4 years ago
Which one of the following lines best illustrates personification?
jekas [21]
C. A narrow wind complains all day.

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