√3 - √169 =?
√3 - √(13)² = √³ - 13 or equal √3 + 13 since √169 = + or - 13
Answer:
7
Step-by-step explanation:
sing the equation > A = Pe^rt
20000 = 10000e^0.1t > 10% = 0.1
2 = e^0.1t
log 2 = log e^0.1t > log to the base e
log 2 = 0.1t * 1 log e to the base e =1
0.6931 = 0.1t
t = 6.931
= 7 years
Hope this helps <3
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Answer:
17 nickles !
Step-by-step explanation:
First, identify the variables:
n = amount of nickels
d = amount of dimes
Next, setup the equations based on what you know. The first equation is:
n + d = 28
For the second equation, we know that a dime is worth 10¢ and a nickel is 5¢, so it should be:
0.05n + 0.10d = 1.95
This a three-step answer:
In one formula (you can use any of them; most people use the simplest one), single out the variable on one side
Apply the first formula into the second formula, and solve it to get the value of one variable
Apply the answer from the second formula into the first formula, and solve it to get the value of the other variable
======
Step One:
n + d = 28
n + d - d = 28 - d
n = 28 - d
Step Two:
0.05n + 0.10d = 1.95
(0.05 * (28 - d)) + 0.10d = 1.95
1.40 - 0.05d + 0.10d = 1.95
1.40 + 0.05d = 1.95
1.40 - 1.40 + 0.05d = 1.95 - 1.40
0.05d = 0.55
d = 11
Step Three:
n = 28 - d
n = 28 - 11
n = 17
======
Your answer should be 17 nickels and 11 dimes.
You can double check by applying the variables into both formulas.
n + d = 28
17 + 11 = 28
28 = 28
0.05n + 0.10d = 1.95
(0.05 * 17) + (0.10 * 11) = 1.95
0.85 + 1.10 = 1.95
1.95 = 1.95
I hope this helped.
For this case, we have to:
By definition, we know:
The domain of ![f (x) = \sqrt [3] {x}](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%20%5Csqrt%20%5B3%5D%20%7Bx%7D)
is given by all real numbers.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.
So, we have:
![y = \sqrt [3] {x-2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7Bx-2%7D)
with
: ![y = \sqrt [3] {- 2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7B-%202%7D)
is defined.
![y = \sqrt [3] {x+2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7Bx%2B2%7D)
with ![x = 0:\ y = \sqrt [3] {2}](https://tex.z-dn.net/?f=x%20%3D%200%3A%5C%20y%20%3D%20%5Csqrt%20%5B3%5D%20%7B2%7D)
is also defined.
has a domain from 0 to ∞.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.
Thus, we observe that:
is not defined, the term inside the root is negative when.
While 
if it is defined for .
Answer:
Option b
