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zmey [24]
2 years ago
9

Samantha Smith purchased a $50,000 policy for $1,050 per year. After ten years, what will be the ratio (percentage) of

Mathematics
1 answer:
frosja888 [35]2 years ago
4 0

Answer:

After 10 years the ratio will be 10500: 500000

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Find the length of the hypotenuse of a right triangle whose legs have lengths 4 and 8
Irina18 [472]
Ya gotta use the Pythagorean theorem :)

a² + b² = c²      (reminder: c is the hypotenuse)

4² + 8² = c²

16 + 64 = 80

√80 = 8.94

H = 8.94

6 0
3 years ago
Can somebody help me with this?<br>​
miv72 [106K]

Answer:

Its y=1/2x +2(the second one)

Step-by-step explanation:

8 0
2 years ago
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Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units. What would be the perimeters of the
Dmitriy789 [7]

Answer:

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

Step-by-step explanation:

Given - Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units.

To find -  What would be the perimeters of the other rectangles Orbet could make using only these 24 tiles? How do the areas of the rectangles compare?

Proof -

We know that

Are of Rectangle = Length × Breadth

And Perimeter of Rectangle = 2 (Length + Breadth )

Now,

Given that,

Orbet used 24 square tiles

And perimeter of the rectangle made = 20

So,

Possible Length of rectangle = 6

Possible breadth of Rectangle = 4

Or Vice-versa.

Total number of Rectangles possible = 4

Possibilities are -  1 × 24, 2 × 12, 3 × 8, 4 × 6

Case I :

Length of rectangle = 1

Breadth of rectangle = 24

∴ Perimeter of rectangle = 2(1 + 24) = 2(25) = 50 units

Area of rectangle = 1 × 24 = 24 unit²

Case II :

Length of rectangle = 2

Breadth of rectangle = 12

∴ Perimeter of rectangle = 2(2 + 12) = 2(14) = 28 units

Area of rectangle = 2 × 12 = 24 unit²

Case III :

Length of rectangle = 3

Breadth of rectangle = 8

∴ Perimeter of rectangle = 2(3 + 8) = 2(11) = 22 units

Area of rectangle = 3 × 8 = 24 unit²

Case IV :

Length of rectangle = 4

Breadth of rectangle = 6

∴ Perimeter of rectangle = 2(4 + 6) = 2(10) = 20 units

Area of rectangle = 4 × 6 = 24 unit²

∴ we get

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

5 0
3 years ago
I need help solving |5+2j|=9 please
V125BC [204]

5 + 2j = 9 \\ j = 2
5 + 2j =  - 9 \\ j =  - 7
3 0
2 years ago
The access code for a vault consists of four digits. The first digit
Vikki [24]

Answer:

5 * 10 * 10 * 9 = 4500

Step-by-step explanation:

6 0
3 years ago
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