23 centimeters =
We make the following rule of three:
1 centimeter ----> 1 kilometer
23 centimeter -> x kilometer
We clear x:
x = (23/1) * (1)
x = 23 kilometers
0.5 centimeters =
We make the following rule of three:
1 centimeter ----> 1 kilometer
0.5 centimeter -> x kilometer
We clear x:
x = (0.5 / 1) * (1)
x = 0.5 kilometers
9 centimeters =
We make the following rule of three:
1 centimeter ----> 1 kilometer
9 centimeter -> x kilometer
We clear x:
x = (9/1) * (1)
x = 9 kilometers
Answer:
c. 23 kilometers
a. 0.5 kilometers
b. 9 kilometers
Answer:
Third choice:

Explanation:
<u />
<u>1. Data:</u>
<u />

- Cobalt-60's half-life: 5.3 years
- Initial mass of cobalt-60: 50 mg
<u>2. Unknown: </u>
<u />
- equation for the mass of cobalt-60 remaining after 10 years = ?
<u>3. Solution</u>
<em>Half-life</em> is the time it takes a sample to decay to half of its initial amount. It is considered constant. Hence, when one half-life passes, the sample has decayed to 50% of the original amount; when two half-lives pass, the sample has decayed to (1/2)×(1/2) = 1/4 = 25%; when three half-lives have elapsed, the sample has decayed to (1/2)³ = 1/8 = 12.5% of its original amount, and so on.
Then, the amound of a sample remaining is calculated as the original amount times (1/2) raised to the number of half-lives elapsed, which is what the given function,
models.
You just must substitute the data into the function to get the answer to the question:

Where, 50 is the original mass of 50g, 0.5 is equal to 1/2, and 10/5.3 gives the number of half-lives (the number of times that 5.3 years is contained in 10 years).
<u>Simplifying:</u>

Which corresponds to the third choice of the list.
<u>Computing:</u>

Which also corresponds to the third choice.
1105 /5 =221 in each of the 5 glasses
julia gets an extra 22 ml
221+22 = 243 ml
Choice C
Answer:

Step-by-step explanation:
According to the Parallelogram definition, every Parallelogram have a pair of congruent sides. In this case, Namely
and 
(not listed as an option)
And the opposite angles are congruent too.
So
