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FrozenT [24]
3 years ago
11

(3x + 5) (x - 2) Multiply?

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
8 0

Answer:

3x^2-x-10

Step-by-step explanation:

This equation cannot be simplified by much, so, the final answer is still an equation, 3x^2-x-10.

Hope this helped! :)

Sati [7]3 years ago
8 0

Answer:

Here,

(3x+5)(x-2)

=3x^2-6x+5x-10

=3x^2-x-10

=3x^2-6x+5x-10

=3x(x-2)+5(x-2)

=(3x+5)(x-2)

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Select the actual distances represented by the following scale distances if the map scale is 1 centimeter = 1 kilometer
zzz [600]
23 centimeters =
 
We make the following rule of three:
 1 centimeter ----> 1 kilometer
 23 centimeter -> x kilometer
 We clear x:
 x = (23/1) * (1)
 x = 23 kilometers
 0.5 centimeters = 
 We make the following rule of three:
 1 centimeter ----> 1 kilometer
 0.5 centimeter -> x kilometer
 We clear x:
 x = (0.5 / 1) * (1)
 x = 0.5 kilometers

 9 centimeters =
 We make the following rule of three:
 1 centimeter ----> 1 kilometer
 9 centimeter -> x kilometer
 We clear x:
 x = (9/1) * (1)
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 Answer:
 c. 23 kilometers 
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4 0
3 years ago
Read 2 more answers
The function f(h)=m(1/2)^h gives the mass, m, of a radioactive substance remaining after h half-lives. Cobalt-60 has a half-life
goldfiish [28.3K]

Answer:

Third choice:

                f(x)=50(0.877)^{10};13.5mg

Explanation:

<u />

<u>1. Data:</u>

<u />

  • Function:

                f(h)=m(1/2)^h

  • Cobalt-60's half-life: 5.3 years

  • Initial mass of cobalt-60:  50 mg

<u>2. Unknown: </u>

<u />

  • equation for the mass of cobalt-60 remaining after 10 years = ?

  • mass remaining =?

<u>3. Solution</u>

<em>Half-life</em> is the time it takes a sample to  decay to half of its initial amount. It is considered constant. Hence, when one half-life passes, the sample has decayed to 50% of the original amount; when two half-lives pass, the sample has decayed to (1/2)×(1/2) = 1/4 = 25%; when three half-lives have elapsed, the sample has decayed to (1/2)³ = 1/8 = 12.5% of its original amount, and so on.

Then, the amound of a sample remaining is calculated as the original amount times (1/2) raised to the number of half-lives elapsed, which is what the given function,  f(h)=m(1/2)^h models.

You just must substitute the data into the function to get the answer to the question:

            f(x)=50(0.5)^{(10/5.3)}

Where, 50 is the original mass of 50g, 0.5 is equal to 1/2, and 10/5.3 gives the number of half-lives (the number of times that 5.3 years is contained in 10 years).

<u>Simplifying:</u>

f(x)=50(0.5)^{(10/5.3)}=50((0.5)^{(1/5.3})^{10}\approx50(0.877)^{10}

Which corresponds to the third choice of the list.

<u>Computing:</u>

               f(x)\approx50(0.877)^{10}=13.5

Which also corresponds to the third choice.

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3 years ago
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Answer:

15 over 72 is the answer

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Answer:

\angle T \cong \angle R\\\angle S \cong \angle Q

Step-by-step explanation:

According to the Parallelogram definition, every Parallelogram have a pair of congruent sides.  In this case, Namely \overline{RS} \cong \overline{TQ}  and \overline{QR} \cong \overline{TS}

(not listed as an option)

And the opposite angles are congruent too.

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\angle T \cong \angle R\\\angle S \cong \angle Q

5 0
3 years ago
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