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Luden [163]
3 years ago
5

The scale on a map shows that 2 in = 50 km. If there are 5 inches between two cities, what is the actual distance between them?

Mathematics
1 answer:
zzz [600]3 years ago
7 0

Answer:

125km

Step-by-step explanation:

<em>50km</em><em> </em><em>÷</em><em> </em><em>2in</em><em> </em><em>=</em><em> </em><em>25km</em><em> </em><em>per</em><em> </em><em>1</em><em> </em><em>in</em><em>.</em>

<em>5</em><em> </em><em>in</em><em>.</em><em> </em><em>×</em><em> </em><em>2</em><em>5</em><em> </em><em>km</em><em> </em><em>=</em><em> </em><em>125km</em>

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Answer:

A) 34x²

Step-by-step explanation:

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180m

To find this we need to find the perimeter. The perimeter is not given so we need to find it. If the land is square we can assume all sides are the same length. So to find the perimeter we need to find the side length. So we find the square root of the volume. The square root of 2025 is 45. So we now add all the side lengths together. The equation is 45+45+45+45. This makes 180m. It takes 180m of fence.

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Read 2 more answers
The length of the famed fred's fence is 5 more than twice it's width if the perimeter of the fence is 510 feet find the dimensio
Sveta_85 [38]

Answer:

  • 83 1/3 ft wide
  • 171 2/3 ft long

Step-by-step explanation:

Let w represent the width of the area. Then 2w+5 represents the length. The perimeter is twice the sum of length and width:

  P = 2(L+W)

  510 = 2(2w+5 +w) . . substitute given values

  255 = 3w +5 . . . . . . divide by 2

  250 = 3w . . . . . . . . . subtract 5

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  2w+5 = 171 2/3 . . . .  the length of the area

The fenced area is 83 1/3 ft wide and 171 2/3 ft long.

4 0
4 years ago
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