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ValentinkaMS [17]
2 years ago
11

Which of the following is the solution to |x-12 k 15?

Mathematics
1 answer:
lyudmila [28]2 years ago
5 0

Answer:

The answer is option B

Step-by-step explanation:

The solution is in the image

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PLEASE SIMPLIFY THE EXPRESSION!!!!!
slega [8]
(2x24)+(2x42)

I am not sure


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3 years ago
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Tina thinks of two numbers. She says, "My two numbers add up to 12. Three times my first number plus twice my second number is 2
butalik [34]
The first number is 5 and the second number is 7
8 0
3 years ago
A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The​ plate, including the bound
rjkz [21]

Answer:

We have the coldest value of temperature T(\frac{3}{4},0) = -9/16. and the hottest value is T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}.

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x

Let's take the partials derivatives.

T_{x}(x,y)=2x-\frac{3}{2}=0

T_{y}(x,y)=4y=0

So, we can find the critical point (x,y) of T(x,y).

2x-\frac{3}{2}=0

x=\frac{3}{4}

4y=0

y=0

The critical point is (3/4,0) so the temperature at this point is: T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})

T(\frac{3}{4},0)=-\frac{9}{16}    

Now, we need to evaluate the boundary condition.

x^{2}+y^{2}=1

We can solve this equation for y and evaluate this value in the temperature.

y=\pm \sqrt{1-x^{2}}

T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x  

T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2

Now, let's find the critical point again, as we did above.

T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0            

x=-\frac{3}{4}    

Evaluating T(x,y) at this point, we have:

T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2  

T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}

Now, we can see that at point (3/4,0) we have the coldest value of temperature T(\frac{3}{4},0) = -9/16. On the other hand, at the point -(3/4),\frac{\sqrt{7}}{4}) we have the hottest value of temperature, it is T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}.

I hope it helps you!

4 0
2 years ago
The price of a share of stock for company XYZ at the beginning of the week was $23.99. Over the next five days, the share of sto
ladessa [460]
$25.12

Work:

23.99+3.60=27.59

27.59-4.51=23.08

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7 0
3 years ago
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18 2by5-4 1by10 find the difference
luda_lava [24]

Given:

The expression is:

18\dfrac{2}{5}-4\dfrac{1}{10}

To find:

The difference.

Solution:

We have,

18\dfrac{2}{5}-4\dfrac{1}{10}

It can be rewritten as:

=\dfrac{90+2}{5}-\dfrac{40+1}{10}

=\dfrac{92}{5}-\dfrac{41}{10}

Taking LCM, we get

=\dfrac{184-41}{10}

=\dfrac{143}{10}

=\dfrac{140+3}{10}

=14\dfrac{3}{10}

Therefore, the value of the difference is 14\dfrac{3}{10}.

3 0
3 years ago
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